9. What is the volume of the triangular prism below? 5cm 3cm 4cm 3cm

Answer the picture below.

inysia [295]

Answer:

Step-by-step explanation:

function: all the points

note: x intercept is the domain, y intercept is the range

domain must paired with exact range

the domain can be more than 1, but range must be 1.

domain : 3, 5, 0 , -1, -3, -5

range: 1, 3, 4 , -3(there is 2 but we write it one) , -4

and done!

thank you!

4 0

3 years ago

Hey!!! What is −6+(−12)

SSSSS [86.1K]

Answer:

-18

Step-by-step explanation:

Essentially the same as (-6) - 12

7 0

3 years ago

Read 2 more answers

2/3 x 4/7 write the answer in the simplest form

trapecia [35]

Answer:

8/21

I don't think that it can be simplified further....

6 0

3 years ago

Read 2 more answers

An ice cream store has the pricing shown below. You want to determine the best value. The height of the cone is 4.5 in and the d

nignag [31]

Solution:

Step 1:

We will calculate the volume of ice cream in the single scoop

The volume of the ice cream will be

$\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{2}{3}\pi r^3 \\ r=\frac{2in}{2}=1in(cone) \\ h=4.5in \\ r=\frac{3in}{2}=1.5in(radius\text{ of the hemisphere\rparen} \end{gathered}$

By substituting the values, we will have

$\begin{gathered} V=\frac{1}{3}\pi r^{2}h+\frac{2}{3}\pi r^{3} \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5+\frac{2}{3}\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{99}{14} \\ V=\frac{165}{14} \\ V=11.79in^3 \end{gathered}$

Step 2:

We will use the formula below to calculate the volume of the two scoops of ic cream

$\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{4}{3}\pi r^3 \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5in+\frac{4}{3}\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{99}{7} \\ V=\frac{132}{7} \\ V=18.86in^3 \end{gathered}$

Step 3:

We will use the formula below to calculate the volume of the three scoops of ic cream

$\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{6}{3}\pi r^3 \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5+2\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{297}{14} \\ V=\frac{363}{14} \\ V=25.93in^3 \end{gathered}$

For the first ice cream with one scoop

$\begin{gathered} 1in^3=\frac{3.50}{11.79} \\ 1in^3=\text{ \$}0.30 \end{gathered}$

For the second ice cream with two scoops

$\begin{gathered} 1in^3=\frac{4.50}{18.86} \\ 1in^3=\text{ \$}0.24 \end{gathered}$

For the third ice cream with three scoops

$\begin{gathered} 1in^3=\frac{5.50}{25.93} \\ 1in^3=\text{ \$}0.21 \end{gathered}$

Hence,

The final answer is

The triple sold at $5.50 has the best value because it has the lowest price of $0.21 per cubic inch of the ice cream

3 0

1 year ago

A solution is heated from 0°C to 100°C. Between 0°C and 50°C, the rate of temperature increase is 1.5°C/min. Between 50°C and 10

muminat

Answer:

0.6 °C/min

Step-by-step explanation:

The relationship between rates and movement is ...

time = distance/speed

Here, the "distance" is measured in °C, and the "speed" is the rate of change of temperature.

For the first half of the heating, the time required is ...

(50°C -0°C)/(1.5 °C/min) = 50/(3/2) min = 100/3 min

For the second half of the heating, the time required is ...

(100°C -50°C)/(4/10 °C/min) = 50/(4/10) = 125 min

Then the total time is ...

((100/3) +125) min = (475/3) min

And the average rate of temperature increase is ...

total temperature change / total time

= (100°C -0°C)/(475/3 min) = 300/475 °C/min = 12/19 °C/min ≈ 0.6 °C/min

4 0

3 years ago