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2 years ago

11. Explain different types of program control with suitable flow chart. N

1 answer:

5 0

Counting a sequence of statements without any decisions or branches as one control structure (as many computer scientists do),the if, if-else, and if-else-if ladders as one control structure,the three types of loops (while, do-while, and for) as three different control structures,the break and continue statements, in the context of loops, as one more (although this can be debatable),the switch/case control structure as one,the call/return mechanism as one,the ability to specify and call a callback function as one,the goto/label as one,and the setjmp/longjmp non-local goto as one,

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Exercise : Randomizer In this exercise, we are going to create a static class Randomizer that will allow users to get random int

Nutka1998 [239]

Answer:

Here the code is by using java.

Explanation:

//Randomizer.java

public class Randomizer {

public static int nextInt() {

//get random number from 1-10

int randInteger = (int) (Math.random() * (11) + 1);

//if number is greater than 10 or less than 1

while (randInteger > 10 || randInteger < 1) {

randInteger = (int) (Math.random() * (11) + 1);

}

return randInteger;

}

public static int nextInt(int min, int max) {

//formula to get random number from min-max

int randInteger = (int) (Math.random() * (max + 1) + min);

while (randInteger > max || randInteger < min) {

randInteger = (int) (Math.random() * (max + 1) + min);

}

return randInteger;

}

//RandomizerTester.java

public class RandomizerTester {

public static void main(String[] args) {

System.out.println("Results of Randommizer.nextInt()");

for (int i = 0; i < 10; i++) {

System.out.println(Randomizer.nextInt());

}

int min = 5;

int max = 10;

System.out.println("\n Results of Randomizer.nextInt(5,10)");

for (int i = 0; i < 10; i++) {

System.out.println(Randomizer.nextInt(min, max));

}

OUTPUT:

Results of Randommizer.nextInt()

Results of Randomizer.nextInt(5,10)

4 0

3 years ago

A tiny spot on an LCD monitor display screen that permanently remains black when it should be activated and displaying color is

bekas [8.4K]

Answer:

False.

Explanation:

It's called a dead pixel.

6 0

3 years ago

Add the following 2's complement binary numbers. Also express the answer in decimal. a. 01+ 1011b. 11+ 01010101c. 0101+ 110d. 01

kenny6666 [7]

Answer:

(a) 01 + 1011

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 1011

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1 ------------------> + 1 (in decimal)

1 0 1 1 ------------------> - 5 (in decimal)

1 1 0 0 -------------------> - 4 (in decimal)

Explanation for (a)

01 or 0001

Since the most significant bit is 0 (leftmost bit), it shows that it is a positive number. Therefore, it can be directly converted to its decimal representation as follows:

0001 = 0 x $2^{3}$ + 0 x $2^{2}$ + 0 x $2^{1}$ + 1 x $2^{0}$ = 1

0001 is + 1 in decimal.

1011

Its most significant bit(MSB) is 1 showing that it is negative.

Flipping all its bits and adding 1 to the result, will convert it to it's positive counterpart.

i.e 1011 => 0100 + 1 = 0101.

Converting the result (0101) to decimal gives

0101 = 0 x $2^{3}$ + 1 x $2^{2}$ + 0 x $2^{1}$ + 1 x $2^{0}$ = 5

1011 is -5 in decimal

01 + 1011 or 0001+ 1011 = 1100

The result (1100), of the addition of the two numbers, is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1100 => 0011 + 1 = 0100.

Converting the result (0100) to decimal gives

0100 = 0 x $2^{3}$ + 1 x $2^{2}$ + 0 x $2^{1}$ + 0 x $2^{0}$ = 4

Therefore, the result, 1100 is -4 in decimal.

===================================================

(b) 11 + 01010101

Convert the two numbers into their 8-bit representation since one of them is in 8-bit.

PS: Taking 11, its MSB is 1 showing that it is a negative number. Also, it's 8-bit representation will mean pre-padding it with ones(1s) rather than zeros as follows. In other words, pre-padding a 2's complement number is done using its sign bit.

=> 11 = 11111111

=> 01010101

Addition of the two numbers (in their 2's complement form) gives the following:

1 1 1 1 1 1 1 1 ------------------> - 1 (in decimal)

0 1 0 1 0 1 0 1 ------------------> + 85 (in decimal)

1 0 1 0 1 0 1 0 0 -------------------> + 84 (in decimal)

Discard the carry-out bit (1) making the result 01010100

Explanation for (b)

11 or 11111111

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

11111111 => 00000000 + 1 = 00000001

Converting the result (00000001) to decimal gives 1

11 or 11111111 is - 1 in decimal.

01010101

Its MSB is 0 showing that it is also positive. Now, convert to decimal

01010101 = 85

01010101 is + 85 in decimal.

11111111 + 01010101 = 01010100

The result (01010100), is also positive as the MSB is 0. Now, convert to decimal.

01010100 = 84

Therefore the result (01010100) is + 84 in decimal.

===================================================

Convert the two numbers into their 4-bit representations.

=> 0101 = 0101

=> 110 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

0 1 0 1 ------------------> + 5 (in decimal)

1 1 1 0 -----------------> - 2 (in decimal)

1 0 0 1 1 -------------------> + 3 (in decimal)

Dicard the carry-out bit (leftmost bit) to get 0011 as result.

Explanation for (c)

0101

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now, convert to decimal.

0101 = 5

0101 is +5 in decimal.

110 or 1110

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010 = 2

1110 is -2 in decimal

0101 + 110 = 0101+ 1110 = 0011

The result (0011), is a positive number as the MSB is 0.

Converting the result (0011) to decimal gives

0011 = 3

Therefore, the result, 0011 is 3 in decimal.

===================================================

(d) 01 + 10

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 10 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1 ------------------> + 1 (in decimal)

1 1 1 0 ------------------> - 2 (in decimal)

1 1 1 1 -------------------> - 1 (in decimal)

Explanation for (d)

01 or 0001

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now convert to decimal.

0001 = 1

0001 is + 1 in decimal.

1110

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010 = 2

1110 is -2 in decimal

01 + 1011 or 0001+ 1110 = 1111

The result (1111), is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1111 => 0000 + 1 = 0001.

Converting the result (0001) to decimal gives

0001 = 1

Therefore, the result, 1111 is -1 in decimal.

7 0

4 years ago

Which of the following statement is correct ? A . potential difference is measured by ammeter . B . The unit of potential differ

lina2011 [118]

Answer:

C.Battery is a source of potential difference in a circuit.

Explanation:

A battery is a source of electrons and positive ions which sets one of it's terminal (cathode) at negative potential and the other (anode) at positive potential. Hence a battery is a source of electricity(electrons) which sets a potential difference across the battery terminals.

4 0

3 years ago

A ____ is a copy that is kept in case values need to be restored to their original state.

Zepler [3.9K]

A backup is the copy made in this case

5 0

4 years ago