All categories

2 years ago

What are the coordinates of point J’ after the rotation?

Mathematics

1 answer:

olchik [2.2K]2 years ago

6 0

Step-by-step explanation:

(5,4) is the coordinate of the point j after rotation

You might be interested in

Can someone help please

Elis [28]

Answer:

Alternate

Step-by-step explanation:

Because, as you can see, it is alternating

4 0

3 years ago

Find the value of root 121 + 3 over root 125

NemiM [27]

Answer:

$\mathrm{Decimal:\quad }\:1.25219\\\frac{14\sqrt{5}}{25}$

Step-by-step explanation:

$\frac{\sqrt{121}+3}{\sqrt{125}}\\\sqrt{125}=5\sqrt{5}\\=\frac{\sqrt{121}+3}{5\sqrt{5}}\\\sqrt{121}=11\\=\frac{11+3}{5\sqrt{5}}\\\mathrm{Add\:the\:numbers:}\:11+3=14\\=\frac{14}{5\sqrt{5}}\\\mathrm{Rationalize\:}\frac{14}{5\sqrt{5}}:\quad \frac{14\sqrt{5}}{25}\\=\frac{14\sqrt{5}}{25}$

7 0

3 years ago

Read 2 more answers

If the Laffite family deposits $8500 in savings account at 6.75% interest, compounded continuously, how much will be in the acco

vitfil [10]

Answer:

Option b

Step-by-step explanation:

We have a compound interest problem. With an annual interest rate of 0.675 and an initial payment of 8500, with t = 25 years

Then you must use the annual compound interest formula, which is represented by a growing exponential function:

$y = e ^{ht}$

Where:

h is the interest rate of 0.675

y is the money in the savings account as a function of time

Then substitute the values in the formula and we have:

$y = e ^{0.675(25)}$

$y = 45,950.57$

4 0

3 years ago

The fox population in a certain region has a continuous growth rate of 5% per year. It is estimated that the population in the y

kvasek [131]

Answer:

P(t) = A * (1 + r)^t ;

14,922 ;

Year 2013

Step-by-step explanation:

Given the following :

Continuous growth rate(r) = 5% = 0.05

Population in year 2000 = Initial population (A) = 10,100

Time(t) = period (years since year 2000)

Find a function that models the population,P(t) , after (t) years since year 2000 (i.e. t= 0 for the year 2000).

P(t) = A * (1 + r)^t

Trying out our function for t = year 2000, t =0

P(0) = 10,100 * (1 + 0.05)^0

P(0) = 10,100 * 1.05^0 = 10,100

B.)

Use your function from part (a) to estimate the fox population in the year 2008.

Year 2008, t = 8

P(8) = 10,100 * (1 + 0.05)^8

P(8) = 10,100 * 1. 05^8

P(8) = 10,100 * 1.4774554437890625

= 14922.29

= 14,922

c) Use your function to estimate the year when the fox population will reach over 18,400 foxes. Round t to the nearest whole year, then state the year.

P(t) = A * (1 + r)^t

18400 = 10,100 * (1.05)^t

18400/10100 = 1.05^t

1.8217821 = 1.05^t

1.05^t = 1.8217821

In(1.05^t) = ln(1.8217821)

0.0487901 * t = 0.5998151

t = 0.5998151 / 0.0487901

t = 12.293787

Therefore eit will take 13 years

2000 + 13 = 2013

4 0

4 years ago

It’s My Final Test I’m not sure what the answer is

Elena-2011 [213]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers