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Aneli [31]
3 years ago
12

Negative 11/14 times negative (1/17)

Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

Step-by-step explanation:

-  \frac{11}{14}  \times  -  \frac{1}{17}  \\  =  \frac{11}{14 \times 17}  \\  =  \frac{11}{238}

Hope it will help :)

kogti [31]3 years ago
4 0

Answer:

The answer is 11/238

Hope it helps

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ExtremeBDS [4]

Answer: 28.27

Step-by-step explanation: first multiply the radius by itself 3 times 3 = 9

then take 9 and multiply it by 3.14 which is 28.27

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3 years ago
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After a lesson on exponents,Tia went home and said to her mom,"I learned that 10 to the power of 4 is the same as 40,000." She h
White raven [17]

Tia went home and said to her mom,"I learned that 10 to the power of 4 is the same as 40,000."

Tia made a mistake in her thinking. Exponent represents the number of zeros.

10^4 means we multiply 10 four times

10^4= 10*10*10*10=10000

For exponent 4, we put 4 zeros. So answer is 10,000.


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3 years ago
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Translate and solve: 518% of what number is 3885?
PSYCHO15rus [73]

Answer:The answer is 750

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3885/ 750

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If you are using a calculator, simply enter 3885÷750×100 which will give you 518 as the answer.

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3 years ago
The function of a line is y= 3x + 2. What would the slope of its perpendicular be?
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3 years ago
Corey used the regression equation y = 1.505x − 88.21, where x is the temperature and y is the number of swimmers, to determine
blondinia [14]

x is the temperature and y is the number of swimmers. If there are 80 swimmers, then y = 80 instead of x = 80

This is how Corey should have solved

y = 1.505*x - 88.21

80 = 1.505*x - 88.21 <--- replace y with 80

1.505*x - 88.21 = 80

1.505*x = 80 + 88.21 <--- add 88.21 to both sides

1.505*x = 168.21

x = 168.21/1.505 <--- divide both sides by 1.505

x = 111.767

x = 111.8

If there are 80 swimmers at the pool, then the possible outside temperature is roughly 111.8 degrees F. This temperature seems awfully large, so it's possible that Corey's regression equation has limited scope; in other words, it isn't too useful if x is outside a given interval.

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4 years ago
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