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exis [7]
2 years ago
5

Which type of quadrilateral can have exactly 1 pair of parallel sides? D trapezold Brhombus C squara A rectangle help please i n

eed it homework for today.​
Mathematics
1 answer:
Yuliya22 [10]2 years ago
3 0

Answer:

trapezoid

Step-by-step explanation:

By definition, a trapezoid is a quadrilateral with only one pair of parallel sides.

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A diagonal cross section of a sphere produces which two-dimensional shape?
const2013 [10]

<span>A diagonal cross section of a sphere produces a circle.

Regardless of how the sphere is cut, it will form a circle.

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4 0
3 years ago
Which expression below has the same value as<br> 6<br>9?​
Ksenya-84 [330]

Which expression below has the same value as

6

9?​

Answer:

answer is c no because 9 power six so, we have to write 9 number 6 times

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3 0
3 years ago
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Write a division that represents the question: how many 3/8s are in 5/4?
Goryan [66]

Answer:

Think your answer is 3 1/4

8 0
3 years ago
6x=2x+44 solve for x
agasfer [191]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x = 11}}}}}

Step-by-step explanation:

\sf{6x = 2x + 44}

Move 2x to left hand side and change it's sign

⇒\sf{6x - 2x = 44}

Collect like terms

⇒\sf{4x = 44}

Divide both sides of the equation by 4

⇒\sf{ \frac{4x}{4}  =  \frac{44}{4} }

Calculate

⇒\sf{x = 11}

Hope I helped!

Best regards!!

7 0
3 years ago
Read 2 more answers
What is the area of the given figure?
kirza4 [7]

\huge\boxed{192\ \text{in}^2}

There are three parts to this figure: a rectangle and two triangles that are congruent.

We'll add together the area for each to get the total area.

We'll start by finding the area of the rectangle. We don't know its length, so we need to find the bases of the triangles and add them together.

We know that a^2+b^2=c^2. Substitute and solve for a:

\begin{aligned}a^2+6^2&=10^2\\a^2+36&=100\\a^2+36-36&=100-36\\a^2&=64\\\sqrt{a^2}&=\sqrt{64}\\a&=8\end{aligned}

Now, double this to get the total length of the rectangle, which is 16 inches.

The area of the rectangle is equal to its length times its height:

16\cdot9=\underline{144}

Now, we'll find the area of one of the triangles and double it since they're congruent.

The area of a triangle is one-half of its base times its height, which we then double.

2\left(\frac{1}{2}\cdot b\cdot h\right)

The 2 and the \frac{1}{2} cancel each other out.

b\cdot h

Substitute and solve:

8\cdot6=\underline{48}

Finally, add the rectangle's area to the two triangles' area.

144+48=\boxed{192}

6 0
2 years ago
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