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Contact [7]
2 years ago
5

given that y^2=3x+C is a general solution to the differential equation y’-(3x/y)=0, what is a particular solution determined by

the initial condition y=-3 when x=-2?
Mathematics
1 answer:
PolarNik [594]2 years ago
4 0

Since general solution is already given to find the particular solution just plug in the x and y value into the general and solve for C

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frank rented a truck for one day. There was a base fee of 14.95, and there was an additional charge of 78 cents for each mile dr
Gemiola [76]
Answer : 153 miles

Explanation : first take 134.29 & subtract the 14.95 base fee which give you 119.34 . now divide 119.34 by 78 which gives you 1.53. so he drove 153 miles.
equation : 14.95+ 0.78x = 134.29 . to double check just multiply 153 x 0.78 and add $14.95 which gives us the total of $134.29
7 0
2 years ago
Read 2 more answers
The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin
quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

<u>So, </u>According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of <u>The inscribed circle</u>

<u>So, the center of The inscribed circle is the point S</u>

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

<u>So,</u> According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of <u>The circumscribed circle</u>

<u>So, the center of The circumscribed circle is the point P</u>

5 0
3 years ago
PLEASE HELP ME!!!!!!!
Gennadij [26K]
-4x < 20
Divide -4 on both sides and the x would be by itself and 20/4 = 5. Since it is a negative, the sign would switch to >
This would be the inequality : x > 5

Numbers in the solution set would be any number greater than 5
ex: 6, 10, 15
5 0
2 years ago
What is the inverse of the given relation y = 7x² ?
beks73 [17]

Answer:

y = square root(x/7)

Step-by-step explanation:

switch x and y

x = 7y^2

solve for y

x/7 = y^2

square root(x/7) =y

y inverse is

y= square root(x/7)

7 0
2 years ago
Simplify the expression <br> 9− 3(2)2
Kazeer [188]

Answer:

-3

Step-by-step explanation:

9-3(2)2

9-(6)2

9-12

-3

3 0
2 years ago
Read 2 more answers
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