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Contact [7]
3 years ago
5

given that y^2=3x+C is a general solution to the differential equation y’-(3x/y)=0, what is a particular solution determined by

the initial condition y=-3 when x=-2?
Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Since general solution is already given to find the particular solution just plug in the x and y value into the general and solve for C

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Anyone mind helping?
elena-s [515]

Answer:

15 x^8 y^3

Step-by-step explanation:

The area of a rectangle is given by

A = l*w  where l is the length and w is the width

A = ( 5x^6 y^2) *( 3x^2 y)

   = 15 x^(6+2) y^(2+1)

   = 15 x^8 y^3

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2 years ago
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Resuelve las siguientes ecuaciones
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Answer:


Step-by-step explanation:


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3 years ago
Do y’all know the answer to this ?
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LaTesha and Bernard are playing a game. Their scores for five games are shown in the table below. LaTesha’s and Bernard’s Scores
andre [41]

Answer:

The means differ by 1, but the ranges differ by 40.

Step-by-step explanation:

The mean for LaTesha's score is (92+45+67+36+80)/5= 64

The mean for Benards score is (63+68+62+69+53)/5= 63

The range for LaTeshas score is 92-36=56

The range for Benards score is 69-53=16

So, 64-63=1     and        56-16= 40

6 0
3 years ago
Fine the equation, in standard form, of the line passing through the points (3,-4) and (5,1)
Talja [164]

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (3, -4) and (5, 1). Substitute:

m=\dfrac{1-(-4)}{5-3}=\dfrac{5}{2}\\\\y-(-4)=\dfrac{5}{2}(x-3)

The standard form: Ax+By=C

y+4=\dfrac{5}{2}(x-3)           <em>multiply both sides by 2</em>

2y+8=5(x+3)           <em>use distributive property</em>

2y+8=5x+15            <em>subtract 2y from both sides</em>

8=5x-2y+15          <em>subtract 15 from both sides</em>

-7=5x-2y

<h3>Answer: 5x - 2y = -7</h3>
5 0
4 years ago
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