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3 years ago

10

One survey estimates that, on average, the retail value of a mid-sized car decreases by 8% annually. If the retail value of a ca

r is V dollars today, which expression represents the car’s value 1 year later?

1 answer:

ivolga24 [154]3 years ago

6 0

Value in 1 year = V*0.92

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LabTech is a company that manufactures microscopes and other laboratory instruments . On occasion, one of the microscopes is def

Scrat [10]

Answer:

0.0782 (7.82%)

Step-by-step explanation:

The required probability will be found by using the Binomial Distribution which fits the case of n independent events each with a probability of success equal to p with k successes.

The PMF (Probability Mass Function) is

$f(k,n,p)=\binom{n}{k}p^kq^{n-k}$

Where $q = 1-p$

LabTech states that the probability that a microscope is defective is 0.17%, p=0.0017, q=0.9983. We need to know the probability that k=1 microscope is defective out of a set of n=50 of them. We now apply the formula

$f(1,50,0.0017)=\binom{50}{1}0.0017^10.9983^{49}=0,0782$

Which means that there is a 7.82% of probability to get 1 defective microscope out of the first 50

5 0

3 years ago

There is a bag filled with 4 blue and 5 red marbles.

Oxana [17]

Answer:

1/9

Step-by-step explanation:

there are 9 marbles in all so the probability of getting 1 blue marble would be 1/9

7 0

3 years ago

From 1000, create a pattern by subtracting 8 from each number and stop at 5 numbers

shusha [124]

Well subtract 8 from 1000 and then do that five times. so 992,984,976,968, and 960<span />

7 0

3 years ago

WIll mark BRAINLIST plz help

Pani-rosa [81]

F(-1) = 2(-1)^2 + 8(-1)
= 2(1) + (-8)
= -6

3 0

3 years ago

Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)

timama [110]

<h3>Answer: c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

$f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\$

With a = -5 and b = 4, we have

$f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\$

So,

$f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\$

Use algebra to solve for c

$-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\$

6 0

3 years ago