<h2>
Hello!</h2>
The answer is:
The range of the function is:
Range: y>2
or
Range: (2,∞+)
<h2>
Why?</h2>
To calculate the range of the following function (exponential function) we need to perform the following steps:
First: Find the value of "x"
So, finding "x" we have:

Second: Interpret the restriction of the function:
Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.
So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.
Hence, the range of the function is:
Range: y>2
or
Range: (2,∞+)
Note: I have attached a picture (the graph of the function) for better understanding.
Have a nice day!
Andy picked 5
brianna picked 3 more then andy...she picked 8
carley picked 16
carley picked 2 times as many tulips as brianne....because carley picked 16 and brianna picked 8
I'd use synthetic div. here, with 2 as my divisor:
________________
2 / 1 -11 18
2 -18
----------------------------
1 -9 0
Note that the coefficients of the missing factor are given here and are 1 and -9. Thus, (x-9) is the missing factor.
Answer:
Two subsets that form set of real numbers
You can take positive numbers and negative numbers subset
One subset become (- infinity,0]
other subset (0, infinity)
Answer:
x=1 or x=−2
Step-by-step explanation:
16x2+10x−27=−6x+5
Step 1: Subtract -6x+5 from both sides.
16x2+10x−27−(−6x+5)=−6x+5−(−6x+5)
16x2+16x−32=0
Step 2: Factor left side of equation.
16(x−1)(x+2)=0
Step 3: Set factors equal to 0.
x−1=0 or x+2=0
x=1 or x=−2