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3 years ago

Suppose we have function defined by : f(x)= -3x+7 what values of x give f(x) =-17?

Mathematics

1 answer:

Leya [2.2K]3 years ago

6 0

Answer:

x = 8

Step-by-step explanation:

if f(x) = -17

then we can type:

- 3 x + 7 = -17

solving for "x", subtract 7 from both sides

- 3 x = - 17 - 7

- 3 x = - 24

divide both sides by -3 to isolate "x"

x = -24 / (-3)

x = 8

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Please help me with these 19 and 20 and tell me what you use to get the answer

ss7ja [257]

36 + h = 75...subtract 36 from both sides
h = 75 - 36
h = 39

-176 = h + (-219)
-176 = h - 219....add 219 to both sides
219 - 176 = h
43 = h

6 0

3 years ago

Read 2 more answers

Kelley Katherine takes a trip to Paris. When she was standing near the 1063 foot tall Eiffel tower, she noticed that her shadow

alina1380 [7]

In order to complete this, we must write it as a ratio. This would look like: 2.4:5.25=x:1063. In order to solve for x, we must first divide 5.25 by 2.4, which I will mark as y, then we take y and divide it into 1063, giving us the answer of 485.94, rounded will give you 486. x now equals 486.

5 0

4 years ago

F(x)=2x^2+3 when x=3

Rudik [331]

2x^2+3
x=3
2(3)^2+3
2(9)+3
18+3
21 is the answer.

5 0

3 years ago

How do you write the equation of this description: the graph of a parabola has a vertex of (2,3) and vertically stretched by 3

Mademuasel [1]

The equation of parabola is y = 3x²- 12x+ 15.

<u>Step-by-step explanation:</u>

The equation of the parabola is given as y = x².

If it has a vertex then the equation can be written as,

y = a(x-h)² + k

where (h, k ) is the vertex and a is the stretching or compressing factor.

So here the vertex is (2,3) and it is vertically stretched by 3.

So the equation is given as,

y = 3(x-2)² + 3

y = 3(x² -4x+4) + 3

= 3x² - 12x + 12 + 3

y = 3x²- 12x+ 15 is the equation of the parabola.

3 0

3 years ago

Find equations of the line that is parallel to the z-axis and passes through the midpoint between the two points (0, −4, 9) and

Lorico [155]

Answer: x = -4, y = 0.5, z = 5 +t

Hi!

The line L whose direction is parallel to vector V a passes through point A

is parametrized

$P_L = Vt + A$

Where t, is a real number, and $P_L$ is a any point on line L.

In this case the direction is that of the z-axis , so V = (0, 0, 1)

A is the midpoint between points B = (0, -4, 9) and C=(-8, 5, 1)

The midpoint is A = (B + C)/2 = (-4, 0.5, 5)

Then the line is:

$P_L = (0,0,1) t + (-4, 0.5, 5)$

The equations for each coordinate are:

$x = -4\\y = 0.5\\z = 5 + t$

7 0

3 years ago