Answer:
13
Step-by-step explanation:
Answer:
39 ft²
Step-by-step explanation:
Area of a triangle = 1/2bh
Let:
base = b = 4 ft
height = h = 3 ft
Solve for the area of the triangle:
A = 1/2(4)(3)
A = 2 * 3
A = 6 ft²
Area of a rectangle = bh
Let:
base = b = 9 ft
height = h = 5 ft
Solve for the area of the rectangle:
A = (9)(5)
A = 9 * 5
A = 45 ft²
Subtract the area of the triangle from the area of the rectangle:
45 - 6 = 39 ft²
39 ft² is your answer.
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Answer:
The correct option is (B)
(B) x-y = 6 , 3x+4y = 4
Step-by-step explanation:
As we can see in the graph given below, both lines intersect at (4, -2), which should be the solution of given equations:
Find the values of x and y for (B);
x - y = 6 ⇒ (i)
3x + 4y = 4 ⇒ (ii)
Lets consider equation (i)
x - y = 6
x = 6 + y
Substitute in equation (ii)
3(6+y) + 4y = 4
18 + 3y + 4y = 4
7y = -14
y = -2
Substitute in equation (i)
x - (-2) = 6
x + 2 = 6
x = 6 - 2
x = 4
As solution of part C is also (4, -2), it represents the graph
You can also find the (x, y) for other options the similar way, which will show you they don't have the same value
It is helpful to know several forms of the equation of a line. One that is often overlooked is the intercept form.
.. x/(x-intercept) +y/(y-intercept) = 1
The boundary conditions for your inequalities can be written as the lines
.. x/20 +y/20 = 1
.. x/24 +y/15 = 1
The first inequality will be bounded by the line that has x=20 and y=20 as its x- and y-intercepts. The second inequality will be bounded by the line with x=24 and y=15 as its x- and y-intercepts. Since the inequality conditions include the "or equal to" case, the graphed boundary line will be solid, not dashed. (All but the first graph have these lines properly shown.)
The region shaded for each inequality will be the half-plane (or its portion in the first quadrant) where the x- and y-values make the inequality true. For this problem, that is values of x and y to the left/below the line in both cases. Graph (c) shows where these "feasible regions" overlap, so is the correct choice.
Multiply by the opposite sign the denominator. In the denominator we have the difference of squares.
