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Temka [501]
3 years ago
7

What is the sum of all the positive integers from square root 14 to square root 80

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

The sum is 30.

Step-by-step explanation:

\sqrt{14}=3.74\\\sqrt{80}=8.94\\4+5+6+7+8 = 30

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Factor the expression -24x -30
morpeh [17]

Answer:

-6(4x+5)

Step-by-step explanation:

-24 = -6 * 4

-30 = -6 * 5

6 is a common factor of both 24 and 30.

-6(4x) = -24x

-6(5) = -30

6 0
2 years ago
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8 two ninths – 2 two over three
almond37 [142]

Answer:

8 2/9 - 2 2/3 = 50/9 = 5 5/9

Step-by-step explanation:

So the answer would be B.

4 0
2 years ago
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What are the numbers of pi
gizmo_the_mogwai [7]

Answer: 3.14

Step-by-step explanation: it goes on forever but that is what most people use to calculate with

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3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
Construct parallelogram PQRS<br>with |PQ|=10cm, |ps|=8cm and<br>&lt;QPS = 120​
IgorC [24]

Find sketch of parallelogram attached

Answer and explanation:

A parallelogram is a quadrilateral which is wider than it is long. A parallelogram has two sides parallel to the other. From the above, we are told the parallelogram PQRS has an angle QPS 120, with sides 10cm and 8cm, we use this to sketch the parallelogram

We find that angle QPS is 120 degrees hence angle RSP is 60 degrees since angle on straight line is 60 degrees from 180-120 in angle QPS and alternate angles are equal. Also opposite angles of a parallelogram are equal

4 0
3 years ago
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