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Marina86 [1]
2 years ago
8

The box-and-whisker plot below represents some data set. What percentage of the

Mathematics
1 answer:
myrzilka [38]2 years ago
4 0

Answer:

25 percent; each section of the box plot counts as 25%

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3 1/2 - 4 2/5<br> how do i do this?
Nadusha1986 [10]

Answer:

Ok so first you would have to turn them into improper fractions which is

3 \frac{1}{2\\} = \frac{7}{2} and 4 \frac{2}{5} = \frac{22}{5}

So now that you have made them both improper fractions you have to find common denominators.

To find common denominators you must multiply both the numerator and the denominator by the same thing. Since your oposing fraction has a denominator of 5 you can know that a even number wont go in an odd number so take \frac{22}{5} and mutiply both numbers by 2 and get \frac{44}{10}. Then mutiply both numbers in \frac{7}{2} by 5 to get a common denominator.

\frac{35}{10}

\frac{35}{10} - \frac{44}{10} =35 - 44 = -9 so your answer is -\frac{9}{10}

Step-by-step explanation:

5 0
3 years ago
What is the area of the parallelogram
GaryK [48]
Easy:

formula for parallelogram is b times h

so 5 times 14 =

70 sq mm.
3 0
3 years ago
Read 2 more answers
For each parallelogram find the length of the base or height the first parallelogram has the area of 60 meters square the base i
Lynna [10]

Answer:

  5 m

Step-by-step explanation:

You know the area of a parallelogram is the product of its base length and height:

  area = base × height

Fill in the given values, and solve for height:

  60 m² = (12 m) × height

  (60 m²)/(12 m) = height = (60/12) m

  height = 5 m

The height is 5 meters.

5 0
3 years ago
find the z scores that seperate the middle 82% of the distribution from the area in the tails of the standard normal distributio
Anna [14]

Answer:

Step-by-step explanation:

It’s 4

7 0
3 years ago
How to solve this question
VMariaS [17]
<span>The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

<span>\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2

Since variance has to be 14, we set \sigma^2  = 14 and solve for m

14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\&#10;14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\&#10;0 = \frac{-88}{9}  -\frac{14}{9}m + \frac{2}{9}m^2&#10;

quadratic formula


m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\&#10;m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \frac{10}{3}  }{\frac{4}{9} } \\&#10;m = 11, -4

-4 doesnt' work as it is not a positive integer

m = 11


</span></span>
5 0
3 years ago
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