2 years ago

Which angles are correspoding angles

1 answer:

7 0

Answer:

When two lines are crossed by another line (which is called the Transversal), the angles in matching corners are called corresponding angles. Example: a and e are corresponding angles. When the two lines are parallel Corresponding Angles are equal.

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-15=2t-11 does any one know it please

Murljashka [212]

Add 11 to both sides:

-4=-2t

divide 2 by both sides

2=t

Hope it helps! Comment if you have any questions!

5 0

2 years ago

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Which table represents the same relation as the set StartSet (negative 6, 4), (negative 4, 0), (negative 3, 2), (negative 1, 2)

g100num [7]

Negative 4,0 because I know it

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2 years ago

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Is this right or wrong? Put these numbers in order from the smallest to the biggest. -1/5, -2/3, 2, 4.

quester [9]

Answer:no the -2/3 should be before -1/5

Step-by-step explanation:

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2 years ago

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A shape is made of 9 right triangles of equal size and three identical rectangles. Each rectangle measures 7 mm wide and 3 mm hi

e-lub [12.9K]

Answer:

Step-by-step explanation:

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2 years ago

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Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

Feliz [49]

Your question seems a bit incomplete, but for starters you can write

$\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}$

Expanding where necessary, recalling that $(1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x$ , you have

$\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}$

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

Now, since $1+\tan^2x=\sec^2x$ , the final form could also take

$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

or

$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$

7 0

3 years ago