Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
Answer:
The area of a triangle is the base times height times 1/2. Please mark brainliest!!!!
Answer: The first option with sss as part of the proof
Step-by-step explanation:
The lengths of the arcs drawn in the constructions are the same, so when the line is drawn, the lengths of the sides will all be the same. SSS is proof of congruence.
CPCTC is an acronym for "corresponding parts of congruent triangles are congruent."
Answer:
The correct option is C) The results were not statistically significant but were practically significant.
Step-by-step explanation:
Consider the provided information.
They found that the difference in these shelf lives had a p-value of 0.24. Assume an α of 0.05.
We reject the null hypothesis if p value is less than α.
We are fail to reject null hypothesis if p value is greater or equal to α.
Here p value is greater than 0.05.
So, we do not reject null hypothesis and conclude that result is not statistically significant. But, there is a practical difference between 3 days and 7 days.
Therefore, the correct option is C) The results were not statistically significant but were practically significant.
Answer:
T = - 3.2e + 80
Step-by-step explanation:
Given the following :
e = elevation in thousands of feets
T = temperature (°F)
e1 = 5 ; e2 = 10 (in thousands of feet)
T1 = 64° ; T2 = 48°
y = mx + c ; T = me + c
y = ; m = slope, c = intercept
64 = m5 + c - - - - (1)
48 = m10 + c - - - - (2)
From (1)
c = 64 - m5
Substitute c = 64 - m5 into (2)
48 = m10 + c - - - - (2)
48 = m10 + 64 - m5
48 - 64 = 10m - 5m
-16 = 5m
m = - 16 / 5
m = - 3.2
Substitute the value of m into c = 64 - m5
c = 64 - 5(-3.2)
c = 64 - (-16)
c = 64 + 16
c = 80
Inserting our c and m values into T = me + c
T = - 3.2e + 80
Where e is in thousands of feet
T is in °F
