Answer : 2√3
<u>Given </u><u>:</u><u>-</u>
- A equilateral triangle with side length 4.
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- The value of x in the given figure.
As we know that in a equilateral triangle , perpendicular bisector , angle bisector and median coincide with each other .
- So the perpendicular drawn in the figure will bisect the given side .
- Therefore the value of each half will be 4/2 = 2 .
Now we may use Pythagoras theorem as ,
→ AB² = BC² + AC²
→ 4² = 2² + x²
→ 16 = 4 + x²
→ x² = 16-4
→ x² = 12
→ x =√12 = √{ 3 * 2²}
→ x = 2√3
<u>Hence </u><u>the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>2</u><u>√</u><u>3</u><u> </u><u>.</u>
I hope this helps.
For this case we have the following expression:
Since the denominator is equal, then we can add the numerator.
We have then:
Adding similar terms we have:
Rewriting we have:
Doing common factor in the numerator we have:
Factoring the denominator we have:
Canceling similar terms we have:
Answer:
The simplest form of the expression has 7 in the numerator and m+4 in the denominator.
Answer:
a) the proportion is 0.159 (15.9%)
b) the proportion is 0.524 (52.4%)
c) Ralph is 70.958 inches tall
Step-by-step explanation:
defining our random variable X= heights of men , then we can define the standard random variable Z as
Z= (X- μ)/σ , where μ is the population's mean and σ is the corresponding standard deviation of X
then for X=72
Z= (X- μ)/σ
Z= (72-68)/4 = 1
a) P(X> 72) = P(Z> 1) = 1-0.841 = 0.159 (using standard normal distribution tables)
b) for X=64 and X=74
Z₁= (64 -68)/4 = -1
Z₂= (74-68)/4 = 1.5
then
P(68<X< 74) = P(-1<Z <1.5) 0 = P(Z<1.5) - P(Z<-1) = 0.933- 0.159 =0.774
c) Z₃ = 0.933 - 0.774*0.25 = 0.7395
thus
Z₃= (X₃- μ)/σ →X₃ =μ+ Z₃*σ = 68 + 0.7395*4 = 70.958 inches
therefore Ralph is 70.958 inches tall
https://jhmsmath.weebly.com/uploads/2/7/7/5/27756807/8th_grade_countdown.pdf go to this link page 52-54
Answer:
5.86cm²
Step-by-step explanation:
Area of the shaded region = Area of the rectangle - Area of the circle
Area of rectangle = Length * Width
Area of rectangle = 3cm * 3cm
Area of rectangle = 9cm²
Area of the circle = πr²
Given radius r = 1cm
Area of the circle = 3.14(1)²
Area of the circle = 3.14cm²
Area of the shaded region = 9 - 3.14
Area of the shaded region = 5.86cm²
