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kicyunya [14]
2 years ago
9

Math problem please help me

Mathematics
1 answer:
dangina [55]2 years ago
4 0

Answer- 400 i think

A=2(wl+hl+hw)

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Pattern A follows the rule "add 3" and Pattern B follows the rule "add 4." Pattern A 1 4 7 10 13 Pattern B 5 9 13 17 21 Which or
IceJOKER [234]

Answer:

(1,5) (7,13) (10,17) (7,13)

Step-by-step explanation:

1 4  7  10  13

5 9 13 17 21

6 0
2 years ago
When the expression 3(n + 7) is evaluated for a given value of n, the result is 33. What is the value of n.
Scorpion4ik [409]

Answer:

i think n = 4

Step-by-step explanation:

3(n+7) = 33

3n+21 = 33

3n = 12

n = 4

4 0
2 years ago
Read 2 more answers
1. Using the algebraic expression 6p + 5 = c. Where p represents packs of cards and c represents cost. Solve for the number of p
Scilla [17]
1.) 8
2.) 7
3.) 16
4.) 4
5.) -6
7 0
3 years ago
Once again I’m co fused lol
Leno4ka [110]

A to the middle one

B to the top one

C to the bottom one  

The top one is all real numbers because any number in the "l l" absolute brackets will come out to be positive, example: l-3l=3 and l3l=3. Thats going to be equal to and since the sign says "less than or equal to" that will work.

The middle one is only positive solutions because for 7x to be more than lxl it would need to be positive since the sign is "greater than"

The bottom one is none because the absolute of anything will always be more than a negative since the absolute is always positive. Never less or equal to a negative, always more.



7 0
3 years ago
A new neighborhood activity complex is being built in erie. The perimeter of the rectangular playing field is 256 yards. The len
maw [93]

Answer:

The length of the rectangular playing field is 84 yards and the width is 44 yards

Step-by-step explanation:

Let

x ------> the length of the rectangular playing field

y -----> the width of the rectangular playing field

we know that

The perimeter of the rectangular playing field is equal to

P=2(x+y)

P=256\ yd

so

256=2(x+y) ------> equation A

we have that

x=2y-4 -----> equation B

Solve the system by substitution

Substitute equation B in equation A and solve for y

256=2(2y-4+y)

128=3y-4

3y=128+4

3y=132

y=44

Find the value of x

x=2(44)-4=84

therefore

The length of the rectangular playing field is 84 yards and the width is 44 yards

4 0
3 years ago
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