The Slope of a Line
Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

The graph provided suggests the use of the points (3,-3) and (5,-3). The slope is:

The slope of the line is 0. It corresponds to a horizontal line
Answer:
Step-by-step explanation:
3x² -2 =3*(-3)²-2=3*9 - 2
= 27 - 2
= 25
Answer:
x = -5
y = -1
Step-by-step explanation:
here's the solution :-
- subtracting equation 1 from equation 2 we get,
=》-8x - 4y + 8x - 6y = 44 - 34
=》-10y = 10
=》y = -1
plugging the value of y in equation 2 we get :-
=》-8x - 4y = 44
=》-8x - (4 × -1) = 44
=》-8x + 4 = 44
=》x = 40 ÷ -8
=》x = -5
We can solve this pretty easily using a proportion where x equals the number of cloudy days in the year:
2/5 = x/365
Now cross multiply:
730 = 5x
And finally divide both aides by five:
146 = x
So 146 days of the year were cloudy.
Hope I helped, and let me know if you have any questions!
The first answer is 1 and the second is 0.83333.