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Sati [7]
3 years ago
12

A rabies clinic charges $5.00 for vaccination each vaccine cost. $0.48 a syringe and needle cost 0.09 and the labor for the vete

rinarian is $1.35 if 168 pets are vaccinated what is the profit after all expenses?

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0
This is the answer that I came out with. Hope it helps.

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Identify the mean and standard deviation of the graph
fgiga [73]
The answer is C, mean =100 and standard deviation=15
5 0
3 years ago
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
3 years ago
The difference between 33 1/3% and 33%
Luden [163]

Answer:

_

1/3, or 0.3 is there difference

6 0
3 years ago
If f(x) = x2 – 6x + 14, what is f(-2)?
Paraphin [41]

Answer: −28

i think ?????

4 0
3 years ago
Read 2 more answers
Which expression can be used to find 38% of 20
lubasha [3.4K]

Answer:

A.

Step-by-step explanation:

38% = 38/100 = 0.38

A percentage is anything over 100

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2 years ago
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