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Paha777 [63]
2 years ago
14

A rectangular prism has a height of 4.5 cm, length of 7.2 cm and a width of 9 cm. Joe is going to cover the sides only. How much

paper will he need?
Mathematics
1 answer:
Andru [333]2 years ago
6 0

Answer:

210.6cm^2

Step-by-step explanation:

1) In the diagram below the shape of the rectangular prism is shown:

where L=7.2, W= 9 and H=4.5

In order to cover only the sides, the area of the front and back faces and the side faces should be added, the top and bottom faces should not be

so the area of front and back faces= 2 (length *width) (multiply by 2 to account for both the front and back face, instead of just one face)

=2(7.2)(9)= 129.6 cm^2

area of side faces: 2(W)(H)=2*9*4.5=81cm^2

129.6cm^2+81cm^2=210.6 cm^2

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5y - 3y + 12

Because there is not a common factor between the three terms in it's current state, we must simplify.

2y + 12

Now, we can simplify using the distributive property.

Factor 2.

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An e-commerce research company claims that 60% or more graduate students have bought merchandise on-line at their site. A consum
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Answer:

z=\frac{0.55 -0.6}{\sqrt{\frac{0.6(1-0.6)}{80}}}=-0.913  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduate students show that only 44 students have ever done so is not significantly lower than 0.6

Step-by-step explanation:

Data given and notation

n=80 represent the random sample taken

X=44 represent the students that have bought merchandise on-line at their site

\hat p=\frac{44}{80}=0.55 estimated proportion of graduate students show that only 44 students have ever done so

p_o=0.6 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of interest is lower than 0.6 or 60%, so then the system of hypothesis are.:  

Null hypothesis:p \geq 0.6  

Alternative hypothesis:p < 0.6  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.55 -0.6}{\sqrt{\frac{0.6(1-0.6)}{80}}}=-0.913  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed for this case is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduate students show that only 44 students have ever done so is not significantly lower than 0.6

5 0
3 years ago
The length of a rectangular deck is 3 times its width. If the deck’s perimeter is 32 feet, what is the deck’s area?
Naya [18.7K]
Length of rectangular = 3w
P=2L+2w
32=2L+2w
16=L+w
16=3w+w
16=4w
w=4
L=3*4=12
Area= Lw
Area=12*4= 48 ft^2
3 0
3 years ago
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