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wlad13 [49]
4 years ago
5

3

Mathematics
1 answer:
zheka24 [161]4 years ago
4 0
B infinite solutions,
Because both left hand and right hand sides are equal
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What is the answer? <br> 8 x 1/2 = ______
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Answer:

4

Step-by-step explanation:

Another way to write this is 8/1 x 1/2. Then the answer would be 8/2. Simplify to get 4.

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Which represents discrete data? Question 17 options: A) The price of hamburger meat per pound B) The volume of water in a swimmi
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Step-by-step explanation:

The Number Of pen in a package.

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8<br> What is 5.618372 rounded to the nearest tenths place?
yarga [219]
Answer: 5.6
explanation: the hundredths place is 1, you will not round up but if it was a number that was greater than 4 then you will.
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3 years ago
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The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
Look at the problem above and please tell me which is correct
vagabundo [1.1K]

I think it's the third 4 ( а² + 2а ) + 9

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3 years ago
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