I think you can put bench mark place valie round tenth thousnadth
(5,-3) (-1,6)
y=mx+b
calculate m:
(-3-6)/(5-(-1)
=-9/6=-1.5
y=-1.5x+b
insert the (5, -3) point to calculate b:
-3=-1.5*5+b
-3=-7.5+b
4.5=b
b=the y intercept, so the line intercepts x=0 at y=4.5
If secant of theta =
<span>
<span>
<span>
1.0416666667
</span>
</span>
</span>
then
theta = 16.26 Degrees
cotangent of theta = 3.4286
