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Nesterboy [21]
2 years ago
6

Help please?? find the area of the rhombus.

Mathematics
1 answer:
sdas [7]2 years ago
8 0

The area of the rhombus with length of diagonals 12 cm and 12 cm is 72 centimetre squared.

<h3>Area of a rhombus</h3>

The area of a rhombus can be represented mathematically as follows:

area of a rhombus  = ab / 2

where

  • a and b are the length of the diagonal

a = 6 + 6 = 12 cm

Therefore, let's find b

tan 45 = opposite / adjacent

tan 45 = 6 / x

x = 6 / tan 45

x = 6 / 1

x = 6

b = 6 + 6 = 12 cm

Therefore,

area = 12 × 12 / 2

area = 144 / 2

area = 72 cm²

learn more on rhombus here: brainly.com/question/27267819

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Step-by-step explanation:


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4 years ago
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8 0
3 years ago
When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
aleksandr82 [10.1K]

Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

x^2-(3x+528)

The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

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6 0
3 years ago
Help 7th grade math pls
madam [21]

Answer:

1,455 feet

Step-by-step explanation:

Step 1:

1 : 75    Ratio Inches to Feet

Step 2:

1 : 75 = 19.4 : x   Equation

Answer:

x = 1,455  Multiply

Hope This Helps :)

4 0
3 years ago
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Brut [27]
You can use desmos! and to solve you find the point(s) where they overlap
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