A fair coin is tossed, and a marble is chosen from the bag whose contents are shown below. 3 red marbles, 3 blue marbles, and 4 green marbles. What is the probability of the coin landing heads up and a blue (B) marble being randomly selected?
2 answers:
Answer:
3/20
Step-by-step explanation:
Red = 3
Blue = 3
Green = 4
Total = 3+3+4 = 10
Pr (red) = 3/10
Pr blue) = 3/10
Pr (green) = 4/10
Where Pr = probability
You either have a head or a tail when tossing a coin
Probability of having head = 1/2
Probability of having tail = 1/2
The probability of the coin landing heads up and blue marble = Probability of head ×Pr (blue)
= 1/2 × 3/10
the probability of the coin landing heads up and blue marble = 3/20
Answer:
3/20
Step-by-step explanation:
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3 dimes= 30 cent
Answer: 7 laps
Step-by-step explanation:
The athlete planned to run 3 miles
1 lap = 3/7 miles
x laps = 3 miles
by proportion :
x × 3/7miles = 3 miles
x = 3 ÷ 3/7
x = 3 x 7/3
x = 7
Therefore: the athlete will run 7 laps
I decided to do a addition problem because based on the answer it couldn't be multiplication, subtraction, or division. Therefore, my problem would look like 15+9=24 birds in total.
First you want to turn 1/3 into 5/15. 2/15 Pounds of granola left.
Hey there!
To find the answer, we can add up the time from both people.
Hope this helps!
