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Reika [66]
3 years ago
11

A fair coin is tossed, and a marble is chosen from the bag whose contents are shown below. 3 red marbles, 3 blue marbles, and 4

green marbles. What is the probability of the coin landing heads up and a blue (B) marble being randomly selected?
Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0

Answer:

3/20

Step-by-step explanation:

Red = 3

Blue = 3

Green = 4

Total = 3+3+4 = 10

Pr (red) = 3/10

Pr blue) = 3/10

Pr (green) = 4/10

Where Pr = probability

You either have a head or a tail when tossing a coin

Probability of having head = 1/2

Probability of having tail = 1/2

The probability of the coin landing heads up and blue marble = Probability of head ×Pr (blue)

= 1/2 × 3/10

the probability of the coin landing heads up and blue marble = 3/20

dem82 [27]3 years ago
4 0

Answer:

3/20

Step-by-step explanation:

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<h3> </h3>
  • To solve this expression, just <u>replace '</u><u>x</u><u>'</u> by the <em>indicated value</em>, being the number 3, and <em>perform</em> the <em>indicated </em>math <em>operations</em>.

{\large \displaystyle \sf {1 \cdot x+9  }}

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{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \ 12 \   }}}}}}\\\\

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{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \ 12 \   }}}}}}\\\\

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