Answer:
hgo87ii76r7687ro
Step-by-step explanation:
Answer:
The area of the box is equal to 9^3 = 729 in^3
729<1000
Step-by-step explanation:
No since the volume of the box is less than the total volume of the cubes

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

Now the zero product property tells us that there are two cases where this is true,

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of

, so

where
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which occurs twice in the interval

for

and

. More generally, if you think of

as a point on the unit circle, this occurs whenever

also completes a full revolution about the origin. This means for any integer

, the general solution in this case would be

and

.
Answer:
60.444
Step-by-step explanation:
Step-by-step explanation:
Assume that

hence,

now,

attached below is the complete solution