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AlekseyPX
2 years ago
9

What is 29x125x317= ???Help

Mathematics
2 answers:
AURORKA [14]2 years ago
8 0

Answer:29x ^442

Step-by-step explanation:

kumpel [21]2 years ago
6 0

Answer:

1149125

Step-by-step explanation:

29x125x317

=29*x125*x317

=29*x442

=29x442

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Tina recorded the number of calories she burned during a bike ride. The graph shows Tina’s calories burned, y, after x hours. If
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Step-by-step explanation:

8 0
3 years ago
If someone has a cube shaped box that measures 9 inches along each edge. Can they fit 1,000 1 square inch cubes inside the box
Stolb23 [73]

Answer:

The area of the box is equal to 9^3 = 729 in^3

729<1000  


Step-by-step explanation:

No since the volume of the box is less than the total volume of the cubes

4 0
3 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
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ohaa [14]

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Step-by-step explanation:

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2 years ago
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vfiekz [6]

Step-by-step explanation:

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hence,

x = x_1 + x_2+....+x_m

now,

E(x) = E(x_1+x_2+---+x_m)\\\\E(x)=E(x_1)+E(x_2)+---+E(x_m)

attached below is the complete solution

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3 years ago
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