Answer: The equation would NOT help us solve for the length and width of the classroom is "".
Step-by-step explanation:
Let y be the width of the rectangular classroom floor and x be the length of the rectangular classroom floor .
Given ,
The perimeter of a rectangular classroom floor is 90 feet.
The length of the floor is twice the width.
i.e. Length =2 (width)
i.e. x= 2y ..(i)
Also, perimeter = 2(length+width)
When we put value of x from (i), we get
Hence, the equation would NOT help us solve for the length and width of the classroom is "".
Answer:
First number is 6
Second number is 2
Step-by-step explanation:
The trick is that we need to set up two equations. Nor simplicity's sake I'm going to say the first number is x and the second number is y.
First we know that the first number (x) is 4 less than the second number (y).
Less means subtraction.
x-4=y
Then we know that 4 times x is 14 more than 5 times the second. More is addition and times is multiplication.
4x=14+5y
Now we use substitution to find out what x (the first number) is, subbing x-4 in for y.
4x=14+5(x-4)
4x=14+5x-20
-x=-6
x=6
First number is 6
Lastly, we sub 6 back into one of the equations. It's easier to us the first equation.
x-4=y
6-4=y
2=y
The second number is 2
5+5
7+3
9+1
8+2
2+8
4+6
6+4
10+0
all these equal 10
27. 27 divided by -9 = -3. The equation would be x/-9=-3
Answer:
A=1
Step-by-step explanation:
7(5a-4)-1=14-8a
35a-28-1=14-8a
35a-29=14-8a
43a-29=14
43a=43
a=1