1. a line with a slope of 1/3 passes through the point (3, 6) . which point also lies on this line?
1 answer:
1) Substituting into point-slope form, the equation of the line is y-6=⅓(x-3), which rearranges to:
- y-6 = ⅓x - 1
- y = ⅓x + 5
So, we can now substitute in the coordinates of each of the options to see which point lies on the line.
- 3 = ⅓(6) + 5 -> 3 = 7, which is false.
- 6 = ⅓(7) + 5 -> 6 = 22/3, which is false.
- -3 = ⅓(-3) + 5 -> -3 = 4, which is false.
- 3 = ⅓(-6) + 5 -> 3 = 3, which is true.
So, the answer is (4) (-6, 3)
2) Substituting into point-slope form, the equation of the line is y - 5 = ¾(x-2), which rearranges to:
- y - 5 = 0.75x - 1.5
- y = 0.75x + 3.5
So, we can now substitute in the coordinates of each of the options to see which point lies on the line.
- 8 = 0.75(6)+3.5 -> 8 = 8, which is true.
- 9 = 0.75(5) + 3.5 -> 9 = 7.25, which is false.
- 1 = 0.75(-1) + 3.5 -> 1 = 2.75, which is false.
- 2 = 0.75(6) + 3.5 -> 2 = 8, which is false.
So, the answer is (1) (6, 8).
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Hey there!
When finding the difference of expressions like these, there's a few things you should keep in mind.
1. When finding the difference of two polynomials, multiply the polynomial that implied to be "negative" by –1 to expand the problem and make it easier to solve.
2. You combine terms based on their unknown terms, like x, y, x², ab, etc. You cannot combine the terms x and x², but you can combine the terms 6b and 8b by adding them.
3. You can rearrange your terms however you see fit. If a polynomial is implied as "positive", you can multiply that entire polynomial by +1 to get rid of the parentheses.
With all that in mind, you can go ahead and solve for your difference, like so:
will be your difference.
Hope this helped you out! :-)
When finding the difference of expressions like these, there's a few things you should keep in mind.
1. When finding the difference of two polynomials, multiply the polynomial that implied to be "negative" by –1 to expand the problem and make it easier to solve.
2. You combine terms based on their unknown terms, like x, y, x², ab, etc. You cannot combine the terms x and x², but you can combine the terms 6b and 8b by adding them.
3. You can rearrange your terms however you see fit. If a polynomial is implied as "positive", you can multiply that entire polynomial by +1 to get rid of the parentheses.
With all that in mind, you can go ahead and solve for your difference, like so:
Hope this helped you out! :-)