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cricket20 [7]
2 years ago
11

What is the surface area of the square pyramid? 30 m 18 m ות 36​

Mathematics
1 answer:
gayaneshka [121]2 years ago
4 0

Answer:

the answer is 5100 im pretty sure.

Step-by-step explanation:

yes

You might be interested in
Evaluate the following expression for w=4. w^-3 =
slega [8]
W^-3
(4)^-3 = 1/(4)^3
1/64.

The solution is 1/64.
6 0
3 years ago
8. 36.8 = [11.5 – (2.5 X 3)]2
Anestetic [448]

Answer:

[11.5-(2.5*3)]^2=16

Step-by-step explanation:

We want to evaluate [11.5-(2.5*3)]^2

Let us evaluate within the parenthesis first:

[11.5-(2.5*3)]^2=[11.5-(7.5)]^2

\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2

We again subtract within the bracket to obtain:

[11.5-(2.5*3)]^2=[4]^2

This finally gives us:

[11.5-(2.5*3)]^2=16

6 0
2 years ago
Hey again.. Please answer!!
Molodets [167]

Answer:

I can't see the question

its too small can you type it out?

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
21. Given the pattern below, which recursive formula represents the number of triangles in this sequence?
Tamiku [17]

Answer:

its 4

Step-by-step explanation:

a 1 = 3 , a n = a n - 1 + 2

because if you aply this to the shapes that you see at problem 21 you will see that it meaches them

6 0
2 years ago
Type the correct answer in each box. (____)
trapecia [35]

Answer:

1. -16; 2. +64; 3. 16

Step-by-step explanation:

The formula for the volume of a cylinder is

V = πr²x

Data:

r = (x - 8)   mm

V = 1024π mm³

Calculations:

1. Find the cubic equation  

V = πr²h

1024π = π(x - 8)² × x

Divide each side by π

1024 = x(x - 8)²  

1024 = x(x² - 16x  + 64)

1024 =    x³ - 16x² + 64x

x³ - 16x² + 64x - 1024 = 0

2. Solve the cubic equation

The general formula for a third-degree polynomial is

f(x) = ax³ + bx² + cx + d

Your polynomial is  

f(x) = x³ - 16x² + 64x - 1024

a = 1; d = -1024

According to the <em>rational roots theorem</em>, the possible roots are

factors of d/factors of a

Factors of d = ±1, ±2, ±4, ±8, ±16, ± 32, ± 64, ±128, ±256, ±512, ±1024

Factors of a = ±1

Potential roots are x = ±1, ±2, ±4, ±8, ±16, ± 32, ± 64, ±128, ±256, ±512, ±1024

That's a lot of possibilities to check by trial and error. I will just use the one that works.

Try x = 16 by synthetic division.

16|1  -16   64  -1024

  <u>|     16     0   1024 </u>

   1     0   64        0

So,

(x³ - 16x² + 64x - 1024)/(x – 16) = x² + 64

and

(x - 16)(x² + 64) = 0

x - 16 = 0        x² + 64 =    0

     x = 16       x²         = -64

                       x          =  ±8i

There is only one real root: x = 16 mm

6 0
3 years ago
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