Answer:
S=4
Step-by-step explanation:
Answer:
2 roots in every case, not all are real.
Step-by-step explanation:
All of these equations are quadratic equations (degree 2). Every quadratic has two roots. They may be identical (looks like 1 root), and they may be complex (zero real roots), but there are always 2 of them.
a) the y-value of the vertex is negative and the parabola opens downward (leading coefficient -5), so there are no real zeros and both roots are complex.
b) each binomial factor contributes a root. Both roots are real.
c) the discriminant is positive, (3²-4·2·1=1), so both roots are real.
Answer:
The answer is 12, subtract 17 from 10 to get 7, then add 7 to 5
Answer:
hope this attachment will help you
Answer:
Step-by-step explanation:
Equation given: y=-6x-5.
In order to find zeros of an equation, substitute y=0 in the given equation.
0=-6x-5
-6x-5=0
-6x=5
Therefore, is zero for our given equation
