It would most likely be 41 because when you would round 41 after you would × 41 times 10 equals 410 then you would round it to 400
Answer:
the answers are p - 6, 3 (1/3p + 3 - 5), and 3 (1/3p - 2)


Hence there is no such natural numbers exist.
An exponential expression is one in which a number has been raised to a certain power.
<h3>What is an exponential expression?</h3>
An exponential expression is one in which a number has been raised to a certain power.
Now;
1) 3^2 . (3^3)^2 . 3^-8 = 3^2 + 6 - 8= 3^0 = 1
2) (3^2) (2.3)^-3/2^-2 = 3^2 . 2^-3 . 3^-3/2^-3 = 1/3
3) (2^-1) . (3 . 2)^4/(3 . 2)^3 = 2^-1. 3^4 . 2^4/ 3^3. 2^3 = 3
4) 2^5 . 3^5 . 6^-5 = 32 * 243/7776 = 1
5) (2^3) . (2 . 3)^-1/2^2 = 2^3 . 2^-1 . 3^-1/2^2 = 1/3
Learn more about exponential function:brainly.com/question/14355665
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