let's start off by keeping in mind that, if you multiply any integer by 2, regardless of what that integer is, you will always get an EVEN integer, say 13 * 2 = 26, or 18 * 2 = 36 and so on.
let' see a few consecutive even integers
2, 4, 6, 8, 10, 12 , 14..............
notice, to get another one from any of them, we can simply hop back or forwards twice, namely 8 ± 2, gives us 6 and 10.
so let's use for our first even integer say "2a".
that simply means our next even integer can just be 2a + 2
and we add 2 again and so on to get all 6 even integers.
now, we know they add sum up to 126.
![\bf \stackrel{1st}{(2a)}+\stackrel{2nd}{(2a+2)}+\stackrel{3rd}{(2a+4)}+\stackrel{4th}{(2a+6)}+\stackrel{5th}{(2a+8)}+\stackrel{6th}{(2a+10)}~~=~~126 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 12a+30=126\implies 12a=96\implies a=\cfrac{96}{12}\implies \boxed{a=8} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{4th}{2(8)+6}\implies 22](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B1st%7D%7B%282a%29%7D%2B%5Cstackrel%7B2nd%7D%7B%282a%2B2%29%7D%2B%5Cstackrel%7B3rd%7D%7B%282a%2B4%29%7D%2B%5Cstackrel%7B4th%7D%7B%282a%2B6%29%7D%2B%5Cstackrel%7B5th%7D%7B%282a%2B8%29%7D%2B%5Cstackrel%7B6th%7D%7B%282a%2B10%29%7D~~%3D~~126%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A12a%2B30%3D126%5Cimplies%2012a%3D96%5Cimplies%20a%3D%5Ccfrac%7B96%7D%7B12%7D%5Cimplies%20%5Cboxed%7Ba%3D8%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Cstackrel%7B4th%7D%7B2%288%29%2B6%7D%5Cimplies%2022)
Answer:
three yards for blue felt and five yards for green
Step-by-step explanation:
divide each by three
Answer:
the anwers is 5
Step-by-step explanation:
Answer:
the rate growed so they are more rapes now than the past decade
Step 1: We make the assumption that 498 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=498$100%=498.
Step 4: In the same vein, $x\%=4$x%=4.
Step 5: This gives us a pair of simple equations:
$100\%=498(1)$100%=498(1).
$x\%=4(2)$x%=4(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{498}{4}$
100%
x%=
498
4
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{4}{498}$
x%
100%=
4
498
$\Rightarrow x=0.8\%$⇒x=0.8%
Therefore, $4$4 is $0.8\%$0.8% of $498$498.
