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erma4kov [3.2K]
3 years ago
15

What is the correct term? Answer choices given

Mathematics
1 answer:
Ierofanga [76]3 years ago
6 0
The answer is circumcenter because it has to do with triangles!

I hope this helped! Brainliest? :) -Raven❤️
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Find the center and radius of (x + 9)^2 + (y + 6)^2 = 9.
VARVARA [1.3K]
You can do this by comparing your equation to the general form of equation of a circle

( x - a)^2 + (y - b)^2 = r^2       where (a,b) is the centre and r = radius:-
(x  + 9)^2   (y + 6)^2 = 9 

so (a,b) = (-9,-6)  and r = 3

so the answer is B
4 0
3 years ago
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Please help with this
sveticcg [70]

It should be B or C

Step-by-step explanation:

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Find product 5% x $38
Liono4ka [1.6K]
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3 years ago
Y B X C W _ … what letter comes next?
maks197457 [2]

Answer:

D

Step-by-step explanation:

Since it goes B and then C it is safe to assume the letters are going in alphabetical order. Therefore, the next letter would be D.

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2 years ago
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The ratio of the width to the length of a rectangle is 2:3, respectively. Answer each of the following. a By what percent would
Elina [12.6K]

Answer:

The percentage increase in Area of rectangle is 200%

Step-by-step explanation:

Given as :

The  ratio of the width to the length of a rectangle is 2:3

Let The length of rectangle = 2 x

Let The width of rectangle = 3 x

∵ Area of rectangle = length × width

So, A_1 = 2 x × 3 x

Or,  A_1  =  6 x²

<u>Again</u>

The increased length of rectangle = 2 x + 2 x = 4 x

The increase width of rectangle = 3 x + 50% of 3 x

I.e The increase width of rectangle = 3 x + 1.5 x = 4.5 x

∵ Increased Area of rectangle = increased length × increased width

Or,   A_2  = 4 x × 4.5 x  = 18 x²

So, The percentage increase in area = \dfrac{A_2 - A_1}{A_1} × 100

Or, The percentage increase in area = \frac{18 x^{2}-6x^{2}}{6x^{2}} × 100

Or , The percentage increase in area = \dfrac{12}{6} × 100

∴ The percentage increase in area  = 200

Hence, The percentage increase in Area of rectangle is 200% Answer

5 0
3 years ago
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