Solve for 2. Round to the nearest tenth, if necessary. B U 67 T x 142°

Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,

Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁, of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

$Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times (720-576)\times (720 - 672)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times 144 \times 48}$ = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

$Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}$

The semi-perimeter, s₂, of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

$Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times (690 -228)\times (690 - 480)}$

$Area\, of \, \Delta ACD = \sqrt{690 \times 18\times 462\times 210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2$

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0

3 years ago

-9 = X / -6 what does the variable

zvonat [6]

Answer:

x= 54

Step-by-step explanation:

-9=x/-6

x-6 on both sides

54= x

6 0

3 years ago

Lynn is knitting a blanket for her cousin. She uses 2/7 of a roll of yarn each day. How much yarn will she use in four days.

Burka [1]

Answer:

1 1/7 of a roll of yarn.

Step-by-step explanation:

<h2>Brainlest Please!</h2>

7 0

3 years ago

Read 2 more answers

If the original rectangle has an area of 2 cm squared and the scaled copied has an area of 50 cm squared what is the scale facto

vazorg [7]

Answer:

The scale factor used to draw the scaled copy is a factor of 5

Step-by-step explanation:

Here, we are interested in calculating the scale factor which was used to transition the original rectangle to the new scaled copy.

Firstly, there is a way to relate how the scale factor of the sides relate to the scale factor of the area. What we are saying here is that the scale factor of the sides is never equal to that of the area;

For a 2 cm^2 area let’s say the sides are 1 by 2 ; this gives us an area as said

Now, to get 50cm^2, we can see that the scale factor of both areas is 25 (2 to 50)

So the area has been scaled 25 times the original area. So how has the sides been scaled?

Using a general principle, the scale used to scale the area is the square of the scale used to scale the sides. What are we saying here? if the area is scaled by 4, then the sides are scaled by 2

So in this particular case, the area is scaled by a factor of 25

Now, the scale factor of the sides will be the positive square root of this which is 5

Hence, we can conclude that the sides of the smaller triangles were each multiplied by 5 to arrive at the sides of the bigger one which makes it that the scale factor used to draw the scaled copy is 5

8 0

4 years ago

Help WILL give brainlest

3241004551 [841]

Answer:

The two green color codes are similar.

Step-by-step explanation:

A contrasting color would aid in the interpretation of this graph.

7 0

3 years ago