Answer:
.764
Step-by-step explanation:
do it on a calculator (TI84)
0.75 is the same thing as 3/4, so you would have driven 3/4 of a mile.
<u>Angie buys</u>
1 Software package + 3 months of game play.
Each software package costs = $20.
Let us assume cost of one month of game play = $x.
Therefore, total cost to Angie for 1 Software package + 3 months of game play = 20*1 + 3x = 20 +3x.
<u> Kenny buys </u>
1 software package + 2 months of game play.
Therefore, total cost to Kenny for 1 software package + 2 months of game play = 20*1 + 2*x = 20+2x.
Their total cost = $115.
Adding their costs and set it equal to 115, we get
<h3>20 +3x + 20+2x = 115.</h3>
Now, we need to solve it for x.
40 + 5x = 115.
5x = 115 - 40.
5x = 75.
Dividing both sides by 5, we get
x= 15.
<h3>Therefore, $15 is the total cost of one month of game play.</h3>
Answer:
There is no enough evidence that the viscosity is not 3000. The viscosity is not significantly different from 3000.
Step-by-step explanation:
We have to perform an hypothesis test on the mean.
The null and alternative hypothesis are:
The significance level is 0.05.
The mean of the sample is:
The standard deviation of the sample is:
The statistic t can be calculated as:
The degrees of freedom are
The P-value for t=-1.338 and df=4 is P=0.2519. The P-value is greater than the significance level, so it failed to reject the null hypothesis.
There is no enough evidence that the viscosity is not 3000.
solution;
a) From the given information,
N = 53,min=42 and max = 129
K = 1+3.322log₁₀53
= 1+3.322(1.724)
= 1+5.728
= 6.728
Number of classes is 7.
b) find the width of the class interval first
width = max – min /classes
= 129-42/7
= 87/7 =12.42
Take the next largest number 13 as class width. Since the minimum value is 42
The lower limit iof the first class could be 40.
So,
The upper limit of the last class is,
40+(13 x 7) = 131
As the upper limit of the last class covers the entire range of values,
It is better to take the lower limit of the first class as 40
The lower limit of the first calss could be 40.