Can't take the square root of a negative so find a domain where it takes squaer root of 0 wich is allowed hold a sec
there
the denomenator can't be 0 so x cannot be 3, it has to be greater
Answer: f(-2) = 8
Step-by-step explanation: On the graph there’s a point (-2,8), so f(-2), which just means -2’s y value on the graph, is 8.
Divide both sides by 2
x^2 = 128/2
Simplify 128/2 to 64
x^2 = 64
Take the square root of both sides;
x = √64
Since 8 * 8 = 64, the square root of 64 is 8
<em>x = -8 and 8</em>
<u>Answer: B -8 and 8</u>
Answer:
Top right (one what has 16cm^2 and 9cm^2)
Step-by-step explanation:
The one in the top right and even though I cannot see what the area is of the biggest square, I can tell what it should be the two smaller squares combined
Hope this helps :)
