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MaRussiya [10]
3 years ago
11

Question 6 What is the missing value of the following synthetic division?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

Hello!

16

Step-by-step explanation:

Because

-5+16=11

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Since this culture of bacteria obeys the law of uninhibited growth. Given that 500 bacteria are present initially, and there are 800 after 1 hour, a growth rate of 0.470003629246 (k value) has been calculated. <span>5243 </span>will be present after 5 hours.
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What is the value of x for the equation 2^5 ∙ 2^x = 2^8
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Answer:

x=3

Step-by-step explanation:

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Mathematics <br><br> Solving inequality
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Answer:

x _> 9 I dont have the symbol on my phone so I just put the greater than sign there

Step-by-step explanation:

1. Subtract 3 from both sides

5x > 48 - 3

2. simplofy 48 - 3 to 45

5x > 45

3. Divide both sides by 5

x > 45/5

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And again I dont have the sign thats why I used the greater than sign

3 0
3 years ago
Please solve this<br> (Rational numbers 8th grade)
pochemuha

                                        Question # 1

Answer:

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}

Step-by-step explanation:

Given the expression

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}

=-\frac{2}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}           ∵  \frac{-2}{3}\times \frac{3}{5}=-\frac{2}{5}

=-\frac{2}{5}+\frac{1}{4}                        ∵   \frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=\frac{1}{4}

\mathrm{Least\:Common\:Multiplier\:of\:}5,\:4:\quad 20

=-\frac{8}{20}+\frac{5}{20}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{-8+5}{20}

\mathrm{Add/Subtract\:the\:numbers:}\:-8+5=-3

=\frac{-3}{20}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

=-\frac{3}{20}

Therefore,

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}

                                               Question # 2

Answer:

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}

Step-by-step explanation:

Given

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}

=-\frac{6}{35}-\frac{1}{6}\times \frac{3}{2}\times \frac{2}{5}\times \frac{1}{14}          ∵    \frac{2}{5}\times \frac{-3}{7}=-\frac{6}{35}

=-\frac{6}{35}-\frac{1}{140}         ∵   \frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=\frac{1}{140}

\mathrm{Least\:Common\:Multiplier\:of\:}35,\:140:\quad 140

=-\frac{24}{140}-\frac{1}{140}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{-24-1}{140}

\mathrm{Subtract\:the\:numbers:}\:-24-1=-25

=\frac{-25}{140}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

=-\frac{25}{140}

\mathrm{Cancel\:the\:common\:factor:}\:5

=-\frac{5}{28}

Therefore,

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}

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4 years ago
What is the greatest common factor of 42, 56, and 112
VashaNatasha [74]

Answer: gcf, hcf, gcd (42; 112) = 14 = 2 × 7: greatest (highest) common factor (divisor), calculated.

Step-by-step explanation:

8 0
3 years ago
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