Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
If f(x) is an anti-derivative of g(x), then g(x) is the derivative of f(x). Similarly, if g(x) is the anti-derivative of h(x), then h(x) must be the derivative of g(x). Therefore, h(x) must be the second derivative of f(x); this is the same as choice A.
I hope this helps.
Answer:
Step-by-step explanation:
Answer:
x=11
m<a=80º
m<b=80º
Step-by-step explanation:
They are congruent so
8x-8=5x+25
8x=5x+33
3x=33
x=11
Answer:
A. Side-Angle-Side (SAS).
Step-by-step explanation:
Sides go first. Side.
Angle next. Angle.
Side again. Side.
You got Side angle side.
