Answer:
<h3>1) 5(7
- x + 8)</h3>
first box: 5 * 7 = 35
35 x^2
second box: 5 * -1 = -5
-5x
third box: 5 * 8 = 40
40
answer: 35 - 5x + 40
<h3>2) 2x(4x^2 + 3x + 6)</h3>
first box: 2x * 4x^2
2 * 4 = 8
x * x^2 = x^3
8x^3
second box: 2x * 3x
2 * 3 = 6
x * x = x^2
6x^2
third box: 2x * 6
2 * 6 = 12
12x
answer: 8x^3 + 6x^2 + 12x
<h3>
3) (tp + 5)(4p - 6)</h3>
top left box: tp * 4p
p * p = p^2
4t
top right box: tp * - 6
-6tp
bottom left box: 5 * 4p
5 * 4 = 20
20p
bottom right box: 5 * - 6
5 * -6 = -11
-11
answer: 4tp^2 - 6tp + 20p - 11
<h3>
4) (4a - 8)(8a - 1)</h3>
top left box: 4a * 8a
4 * 8 = 32
a * a = a^2
32a^2
top right box: 4a * -1
4 * -1 = -4
-4a
bottom left box: -8 * 8a
-8 * 8 = -64
-64a
bottom right box: -8 * - 1
-8 * - 1 = 8
8
32a^2 - 4a - 64a + 8
<em>combine like terms</em>
32a^2 - 68a + 8 = answer
AnswerY=-10/3x+11:
Step-by-step explanation:
M=0--2/-3-4= -10/3
Y-1=-10/3(x-3)
-10/3x+10+1
Y=-10/3x+11
Answer:-4,3
Step-by-step explanation:h,k
Its correct trust x <3
Center:(-4,3)
Answer:
Input
Independent variable
Step-by-step explanation:
we know that
<u>Independent variables</u>, are the values that can be changed or controlled in a given model or equation
<u>Dependent variables</u>, are the values that result from the independent variables
we have the function
In this problem
This is a proportional relationship between the variables d and t
The function d(t) represent the dependent variable or the output
The variable t represent the independent variable or input
Answer:
x= 2 and y = -4
Step-by-step explanation:
8x + 3y = 4 ---------------------------------(1)
-7x + 5y = -34 -----------------------------(2)
Multiply through equation (1) by 5 and multiply through equation(2) by 3
40x + 15y = 20 ----------------------------(3)
-21x + 15y =-102----------------------------(4)
Subtract equation (4) from equation (3)
61x = 122
Divide both-side of the equation by 61
61x/61 = 122/61
(At the left-hand side of the equation 61 will cancel-out 61 leaving us with just x, while at the left-hand side of the equation 122 will be divided by 61)
x = 122/61
x=2
Substitute x= 2 into equation (1)
8x + 3y = 4
8(2) + 3y = 4
16 + 3y = 4
Subtract 16 from both-side of the equation
16-16 + 3y = 4-16
3y = -12
Divide both-side of the equation by 3
3y/3 = -12/3
y = -4
x= 2 and y = -4
