Answer:
The zeros of the function are -0.488 and -7.39
Step-by-step explanation:
Given the quadratic function
f(x) = 2x²+16x-9
The zeros of the function is gotten at when f(x) = 0
2x²+16x-9 = 0
Using the general equation
x = -b±√b²-4ac/2a
From the equation, a = 2, b = 16 and c= -9
x = -16±√16²-4(2)(-9)/2(2)
x = -16±√256-72/4
x = -16±√184/4
x = -16+13.56/4
x = -16+13.56/4 and -16.13.56/4
x = --2.44/5 and -29.56/4
x = -0.488 and -7.39
Answer:
Option B - 35.4 VAC
Step-by-step explanation:
Formula for peak voltage is;
V_p = V_rms × √2
Making V_rms the formula, we have;
V_rms = (V_p)/√2
We are given:Peak voltage: V_p = 50 VAC
Where 50 VAC means 50 Volts AC power
Thus;
V_rms = 50/√2
V_rms ≈ 35.4 VAC
So option B is correct
A I think is the right answer
Answer:
33.42 divided by 6?
Step-by-step explanation:
Answer:
5 = 6q - 30 - 19
5 = 6q - 49
54 = 6q
9 = q
Step-by-step explanation:
