DGFH is a rhombus where E is the midpoint of the lines GE and GF
please look at the image
Answer:
The least she could of spent would be $41
Step-by-step explanation:
He actually borrowed P=21349-3000=18349 (present value)
Assume the monthly interest is i.
then future value due to loan:
F1=P(1+i)^n=18349(1+i)^(5*12)=18349(1+i)^60
future value from monthly payment of A=352
F2=A((1+i)^n-1)/i=352((1+i)^60-1)/i
Since F1=F2 for the same loan, we have
18349(1+i)^60=352((1+i)^60-1)/i
Simplify notation by defining R=1+i, then
18349(R^60)-352(R^60-1)/(R-1)=0
Simplify further by multiplication by (R-1)
f(R)=18349*R^60*(R-1)-352(R^60-1)=0
Solve for R by trial and error, or by iteration to get R=1.004732
The APR is therefore
12*(1.004732-1)=0.056784, or 5.678% approx.
Answer:
Step-by-step explanation:
1. area of square=10²=100 cm²
area of circle=πr²=π×2.5²=6.25π cm²
reqd. area=100-6.25π ≈80.375 cm²
2.
area of circle=π×2.5²=6.25π≈6.25×3.14≈19.625 cm²
area of rectangle=4×3=12 cm²
reqd. area=19.625-12≈7.625 cm²
3.
area of two circles=2×π×3²=18π≈18×3.14≈56.52 cm²
area of square=12²=144 cm²
reqd. area=144-56.52≈87.48 cm²
4.
area of smaller circle=π×4²=16π cm²
area of bigger circle=π×8²=64π cm²
area of two circles=16π+64π=80π cm²
diameter of bigger circle=4+4+8+8=24 cm
diameter of biggest circle=π×12²=144π
area of shaded region=144π-80π=64π≈200.96 cm²
