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1 year ago

Q: The ratio of the numbers of Nick's marbles to Michael's is 3:5. Nick has 36 marbles. If Nick receives

Mathematics

1 answer:

Nataly [62]1 year ago

7 0

Answer:

$\frac{3}{4}$

Step-by-step explanation:

$\frac{3}{5} = \frac{36}{x}$

3x = 36 x 5

3x = 180

x = 60

Michael has 60 marbles.

Nick recieves 9 more marbles so he has 36 + 9 = 45 marbles

The new ratio will be:

$\frac{45}{60}$ = $\frac{3}{4}$

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Answer: 4188.8

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2 years ago

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3 years ago

The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original

evablogger [386]

Here as the Pentagon is regular so it's all sides will be of equal length . And if we assume It's each side be s , then it's perimeter is going to be (s+s+s+s+s) = 5s.And as here , each side is increased by 8 inches and then it's perimeter is 65 inches , so we got that it's side after increament is (s+8) inches and original length is s inches . And if it's each side is (s+8) inches , so it's perimeter will be 5(s+8) and as it's equal to 65 inches . So , 5(s+8) = 65

${:\implies \quad \sf 5(s+8)=65}$

${:\implies \quad \sf 5s+5\times 8=65}$

${:\implies \quad \sf 5s+40=65}$

${:\implies \quad \sf 5s=65-40}$

${:\implies \quad \sf 5s=25}$

${:\implies \quad \sf s=\dfrac{25}{5}=5}$

${:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}$

As we assumed the original side to be s .

Hence, the original side's length 5 inches 

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2 years ago

In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien

diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = $\frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}$

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2 = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) = $\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)}$ = $\frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)}$ = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

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3 years ago

Rewrite the following quadratic functions in intercept or factored form. Show your work.

Dmitry [639]

Answer:

f(x) = 3(x+2)(x-2)

Step-by-step explanation:

We are given the following the quadratic function and we are to rewrite it in intercept or factored form:

$f(x) = 3x^2 - 12$

We can factorize the given function so taking the common factors out of it to get:

$f(x)=3x^2 - 12$

$f(x) = 3 (x^2 - 4)$

The term $(x^2-4)$ is in the form $a^2-b^2$ so it can further be factorized to give:

$f(x) = 3 (x+2)(x-2)$

Therefore, the factored form of the given quadratic function is f(x) = 3(x+2)(x-2).

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3 years ago

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