In order to get who was right we need to solve the expression:
2a^2b(-2ab^3)^-2
The above can be written as fraction to get:
(2a^2b)/(-2ab^3)^2
=(2a^2b)/(4a^2b^6)
=1/2(a^(2-2)b^(1-6))
=1/2a^0b^-5
=1/2b^(-5)
This implies that neither of the was right
Answer:
all you need to do is fine the difference of the numbers
Step-by-step explanation:
The slope:
m = ( y2 - y1 ) / ( x2 - x1 ) = ( 8 2 ) / ( 3 - 2 ) = 6 / 1
m = 6 ( we have the same slope for AB and A`B` )
AB = √[( 3 - 2 )² + ( 8 - 2 )²] = √37
A`B` = 3.5 √37 = 21.29
If y=0, then 0 = 2x - 8
8 = 2x
4 = x