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Trava [24]
4 years ago
10

Raul is attempting to factor the expression 3x^2-14x-5. In his first step, he rewrites the expression as 3x^2+15x-x-5. Which of

the following statements in true about Raul’s work?
A.

Raul’s first step is correct. He should continue to factor the expression.
B.

The two middle coefficients add to the correct number, but do not multiply to the correct number.
C.

The two middle coefficients multiply to the correct number, but do not add to the correct number.
D.

The two middle coefficients do not add or multiply to the correct number.

please answer as soon as possible
Mathematics
1 answer:
Papessa [141]4 years ago
7 0
It would be C and here's why:
you originally start with 3x² - 14x - 5.  The AC method to factoring says you have to get two middle terms that multiply to whatever 3 × -5 is and have to add to -14. Well 3 × -5 is -15. Raul chose two middle terms of 15x and -1x and 15 × -1 is -15 so that part is correct. However 15 - 1 = 14. The middle term of our original trinomial is -14 so "<span>The two middle coefficients multiply to the correct number, but do not add to the correct number."</span>
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40% of lightbulb produced by shining beauty company have suboptimal performance. 5 bulbs are chosen for test. find the probabili
omeli [17]
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4 0
3 years ago
Suppose f is a continuous function on [-2, 2) such that
Leviafan [203]

Answer:

2. a and b only.

Step-by-step explanation:

We can check all of the given conditions to see which is true and which false.

a. f(c)=0 for some c in (-2,2).

According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.

b. the graph of f(-x)+x crosses the x-axis on (-2,2)

Let's test this condition, we will substitute x for the given values on the interval so we get:

f(-(-2))+(-2)

f(2)-2

-1-1=-3  lower limit

f(-2)+2

1+2=3 higher limit

according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.

c. f(c)<1 for all c in (-2,2)

even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.

The final answer is then 2. a and b only.

4 0
3 years ago
For what values of x will the function f(x) = 3x² + 13x - 10 equal zero?
Oduvanchick [21]

Answer:

x = - 5 , x = \frac{2}{3}

Step-by-step explanation:

the values of x that make f(x) zero are the zeros

to find the zeros let f(x) = 0 , that is

3x² + 13x - 10 = 0

consider the factors of the product of  the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 10 = - 30 and sum = + 13

the factors are + 15 and - 2

use these factors to split the x- term

3x² + 15x - 2x - 10 = 0 ( factor the first/second and third/fourth terms )

3x(x + 5) - 2(x + 5) = 0 ← factor out (x + 5) from each term

(x + 5)(3x - 2) = 0

equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

3x - 2 = 0 ⇒ 3x = 2 ⇒ x = \frac{2}{3}

4 0
2 years ago
Use the log table to estimate the value of log10 8.65. A. .9703 B. .9037 C. .9730 D. .9370
Alex_Xolod [135]
A common logarithmic provides the following value for the log10 of 8.65:
<span><span>0.9370161
Which number is closest to this one? 
The answer is D) 0.9370. 
This means that 8.65 = 10^(.9370). Note that that the number is less than 1, since 10^1 is 10, and 8.65 is less than 10. </span></span>
4 0
3 years ago
Read 2 more answers
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