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Advocard [28]
3 years ago
12

Amelia earned $60 for 5 hours of work. What is the unit rate of Amelia's earnings in dollars per hour?

Mathematics
2 answers:
Ratling [72]3 years ago
5 0
I think it is 12.5
or 5
Ksenya-84 [330]3 years ago
4 0
12 dollars per hour 
next time just divide (; 60/5
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Helpp plzzzz help———help
sdas [7]

Answer:

20

Step-by-step explanation:

c= 1.5q + 6 = 36

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q = 20 (30/1.5)

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3 years ago
What is the value of t? 13t - 8.7 = 82.3
Dennis_Churaev [7]

Answer:

7

Step-by-step explanation:

13t = 82.3 + 8.7

13t = 91

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3 years ago
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BC has endpoints B(-3,-5) and C(12,12). FInd the coordinates of the midpoint of BC
forsale [732]

Answer:

(9/2, 7/2)

Step-by-step explanation:

The easiest way to remember how to do this problem is to average the x-coordinates and average the y-coordinates.

So, in your problem (-3 + 12)/2 = 9/2   and  (-5 + 12)/2 = 7/2

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4 0
2 years ago
If h is 36in, w is 28in, and A is 6112in to the second power, what is the length of the box
OlgaM077 [116]
The length of the box would be 12288.
5 0
3 years ago
The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.10
Salsk061 [2.6K]

For the bell-shaped graph of the normal distribution of weights of Hershey kisses, the area under the curve is 1, the value of the median and mode both is 4.5338 G and the value of variance is 0.0108.

In the given question,

The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.1039 G.

We have to find the answer of many question we solve the question one by one.

From the question;

Mean(μ) = 4.5338 G

Standard Deviation(σ) = 0.1039 G

(a) We have to find for the bell-shaped graph of the normal distribution of weights of Hershey kisses what is the area under the curve.

As we know that when the mean is 0 and a standard deviation is 1 then it is known as normal distribution.

So area under the bell shaped curve will be

\int\limits^{\infty}_{-\infty} {f(x)} \, dx= 1

This shows that that the total area of under the curve.

(b) We have to find the median.

In the normal distribution mean, median both are same. So the value of median equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of median is also 4.5338 G.

(c) We have to find the mode.

In the normal distribution mean, mode both are same. So the value of mode equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of mode is also 4.5338 G.

(d) we have to find the value of variance.

The value of variance is equal to the square of standard deviation.

So Variance = (0.1039)^2

Variance = 0.0108

Hence, the value of variance is 0.0108.

To learn more about normally distribution link is here

brainly.com/question/15103234

#SPJ1

3 0
1 year ago
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