Y=-13+1
y=-12
So the "range" is only a single number...-12
B=420-76 this is the answer if you were not referring to the 76 as a percent
Given: F=ma. To solve for a, we isolate a on one side of this equation. To do this, divide both sides of F=ma by m. Then F/m = a.
Thus, if m=10 units, the acceleration is a = F/10 units. Looks as tho' you were given the numeric value of F but did not share that value here.
Solving F=ma for m: m=F/a. Thus, if F=25 units and a=5 units, m=25/5 units, or m=5 units.
(3x - 8y + 7)-(-x + 7y - 6)
9514 1404 393
Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.