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fomenos
3 years ago
6

Can you help me with this?​

Mathematics
1 answer:
Ivanshal [37]3 years ago
3 0

Answer:

(2,-3) and (49/29, -108/29)

Step-by-step explanation: Assuming this is an exam and time is limited, first you gotta sketch the circle for clarity. Using the standard circle equation

(x-a)^2 + (y-b)^2 = r^2

(x-1)^2 + (y+3)^2 =1

You can always expand to verify it gives x^2 + y^2 - 2x + 6y + 9=0

Now you know (a,b) which is also the center of the circle being= (1,-3) and the radius(r) = 1

Your first assumption here even without drawing the circle is that it has to be in the fourth quadrant meaning all values of x for any point of intersection on that circle has to be +ve. Looking at your answer choices only c with is (2,-3) and (49/29, -108/29) fulfills this hence it is your answer.

Also you have to realize point (2,-3) on the straight line has same y coordinates with center of this circle.

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8.71 x 10^3N - C

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Twenty words were randomly selected from two textbooks. Each set gives the number of letters in each of the twenty words for tha
Alborosie

Answer:

k = 13The smallest zero or root is x = -10

Step-by-step explanation:

you can write "x^2" to mean "x squared"

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f(x+5) = (x^2+10x+25)+3(x+5)-10

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Compare this with x^2+kx+30 and we see that k = 13

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3 years ago
The Maine Public Health Department reported that there have been 90 flu cases requiring hospitalization in Portland, ME (populat
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