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3 years ago

Can you guys help me find the mistake??

Mathematics

2 answers:

KIM [24]3 years ago

5 0

Is that the whole question?

katrin2010 [14]3 years ago

4 0

To be honest I don’t know but I think it is line 2 or 3

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Can someone show me how to do this please

marta [7]

Answer:

$volume = 0.32 m^3$

Step-by-step explanation:

The object shown above consists of 5 cubes having side lengths of ⅖m each.

Volume of a cube = $a^3$

Where, a = side length = ⅖ m

Volume of the object = $5* (\frac{2}{5})^3$

$volume = 5*\frac{8}{125} = 5*0.064 = 0.32 m^3$

6 0

3 years ago

What is corresponding angle? give a definition of it

Alchen [17]

Answer:

any pair of angles each of which is on the same side of one of two lines cut by a transversal and on the same side of the transversal.

5 0

3 years ago

Read 2 more answers

(b) Solve and write the solution set<br>for: 3x -8<7 ; XEN<br>

bekas [8.4K]

Answer:

x=5is greater than 7

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6 0

3 years ago

Solve for v: -10=-5/4v

vagabundo [1.1K]

Answer:

v = 8

Step-by-step explanation:

-10= -5/4v first multiply both sides of the equation by -4/5

-10(-4/5) = v this cancels out the right side.

multiply the left side.

so you are left with 40/5 = v

next, simplify you will get 8=v

8 0

3 years ago

Read 2 more answers

Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285

Mkey [24]

Answer:

$Highway = 155\ miles$

$City = 130\ miles$

Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

$Total\ Miles = 285$

$Total\ Gallons = 10$

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

$31h + 26c = 285$ --- distance travelled

In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

$31h + 260 - 26h = 285$

Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

$City = 26 * 5$

$City = 130\ miles$

8 0

3 years ago