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jarptica [38.1K]
3 years ago
8

Can you guys help me find the mistake??

Mathematics
2 answers:
KIM [24]3 years ago
5 0
Is that the whole question?
katrin2010 [14]3 years ago
4 0
To be honest I don’t know but I think it is line 2 or 3
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Find the height of the cone. Round your answer to the nearest whole number.
amm1812

Answer:

3

Step-by-step explanation:

3.34in is ans and after rounding off we can get 3

3 0
3 years ago
Pls answer this question
Paraphin [41]
What is the question
4 0
3 years ago
5•11+5•(-4)=5(11-4) wich property?​
ludmilkaskok [199]

Answer:

Step-by-step explanation:

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3 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
9x^2 - 8x - 1 = 0<br> What are the x intercepts?
sasho [114]
9x^2  - 8x - 1 = 0

(9x + 1(x - 1) = 0

x = -1/9 , 1  

x intercepts are -1/9 and 1.
4 0
3 years ago
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