B
To solve for the inverse, just swap the x and y and solve for the new y.




Then inspect both functions for the domain.
In the original function, x has to be greater than or equal to 0 or else you would have a negative square root which is impossible.
The inverse function has no limitations as any x could make that true.
The main things that will limit domain is square root of negative or divide by zero.
Therefore, x>=0 is the only domain restriction.
Answer:
a.) 1.38 seconds
b.) 17.59ft
Step-by-step explanation:
h(t) = -16t^2 + 22.08t + 6
if we were to graph this, the vertex of the function would be the point, which if we substituted into the function would give us the maximum height.
to find the vertex, since we are dealing with something called "quadratic form" ax^2+bx+c, we can use a formula to find the vertex
-b/2a
b=22.08
a=-16
-22.08/-16, we get 1.38 when the minuses cancel out. since our x is time, it will be 1.38 seconds
now since the vertex is 1.38, we can substitute 1.38 into the function to find the maximum height.
h(1.38)= -16(1.38)^2 + 22.08t + 6 -----> is maximum height.
approximately = 17.59ft -------> calculator used, and rounded to 2 significant figures.
for c the time can be equal to (69+sqrt(8511))/100, as the negative version would be incompatible since we are talking about time. or if you wanted a rounded decimal, approx 1.62 seconds.
Tienes que hallar el mínimo común múltiplo de las 3 cantidades.
18= 2×3²
24= 2³×3
36= 2²×3²
mcm(18,24,36) = 2³×3²=8×9= 72
Eso quier decir que si partieron a la misma hora se encontraran de nuevo en el punto de partida 72 minutos después de la salida.
Las vueltas que habrán realizado será el resultado de dividir 72 entre el tiempo que tardan en dar una vuelta
<span>Mayor: </span> = 4
<span>Mediano: </span> = 3
<span>Pequeño: </span> = 2
Soluciónes:
se vuelven a encontrar a los 72 min de la salida
<span>El mayor dió 4 vueltas, el mediano 3 y el pequeño 2</span>
Pretty sure it would be D
Good luck on your finals!
Answer:
(2x+11)x (2x-11)
Step-by-step explanation: