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4 years ago

Which goes from least to greatest square root 115 155/11 or 10.5624,

Mathematics

1 answer:

Zinaida [17]4 years ago

8 0

115 (10.723)
155/11 (1.1318)
10.5624 (3.2499)

1. 155/11
2. 115
3. 10.5624

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A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med

Troyanec [42]

The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test - No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is $\frac{0.0396}{0.0396+0.0096}= \frac{33}{41}$

The probability of someone picked at random has cancer given that test result indicates no cancer is $\frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}$

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3 years ago

PLEASE HELP 5x-2y=30 What is the y value

Ierofanga [76]

Answer:

y = 5/2x -15

Step-by-step explanation:

5x - 2y = 30

-2y = -5x + 30

y = $\frac{5}{2}$ x -15

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4 years ago

Read 2 more answers

At a wedding reception an equal number of guests were seated at each of three large tables, and 7 late arriving desks were seate

nikitadnepr [17]

Answer:

10 guests a table

Step-by-step explanation:

3 tables

7 late arrivals

37 total people

37 minus 7 is 30

30 divided by 3 is 10

answer is 10

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3 years ago

Mr. Johnson has 4 daughters. Each of his daughters has a brother. How many children does mr. Johnson have?.

777dan777 [17]

Answer:

Step-by-step explanation:

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2 years ago

A car rental agency has 150 cars. The owner finds that at a price of $48 per day, he can rent all the cars. For each $2 increase

hram777 [196]

Given that for each $2 increase in price, the demand is less and 4 fewer cars are rented.

Let x be the number of $2 increases in price, then the revenue from renting cars is given by
$(48 + 2x) \times (150 - 4x)=7,200+108x-8x^2$ .

Also, given that for each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by
$5(150-4x)=750-20x$

Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
 $(7,200+108x-8x^2)-(750-20x)=6,450+128x-8x^2$

For maximum profit, the differentiation of the profit function equals zero.
i.e.
 $\frac{d}{dx} (6,450+128x-8x^2)=0 \\ \\ 128-16x=0 \\ \\ x= \frac{128}{16} =8$

The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.

Therefore, the rental charge will maximize profit is $64.

3 0

3 years ago