Answer:
Explanation: ... To find the product of a binomial and a trinomial, multiply out the brackets: ... Simplify. \[{\left(x - 1\right)\left({x}^{2} - 2x + 1\right)} = {x}^{3} - 3{x}^{2} + 3x - 1\] ... \begin{align*} (-2y^{2} - 4y + 11)(5y - 12) & = -10y^{3} - 20y^{2} + 55y + 24y^{2} + 48y ...
Answer:
6x^2
Step-by-step explanation:
=2x^2•3x^0
=2x^2•3×1 (As any thing to the powe 0 is 1)
=2x^2•3
=2•3x^2
=6x^2
The standard equation is y=ax^2+bx+k and the vertex way is y=a(x-h)(x-h)+x
so the coordinate for x is -b/2a, for your problem a=-4 b=-16 so the coordinate for x is -(-16)/(2*(-4))=-2. Now you have to replace x=-2 in your equation y=-4(-2)^2-16(-2)-11= 5.
The vertex is (-2, 5)
You multiply everything by 3 which equals 3y=2x+21 then you switch 21 and 3y which equals -21=2x-3y. Hope this helps
The position of 7 is in A. The ten-thousands place