Answer:no they are not independent
Step-by-step explanation:
1) in order for events to be independent the probability of E happening should equal the probability of E happening given that F has already happend
2) P(E)=1/6 (on 6 sided die there is only 1 face that has 3 hence probability of e occurring is 1/6) or .167
3) P(E | F) read as probability of E happening given F has occurred
(Probability of E * probability of F) / total number of outcomes in F
probability of F= 1/6 as there is only one face(3) which will make the sum of the 2 die 6
(1/6)(1/6)/6=0.004
P(E)= .1167
P(E| F) =.004
hence probability aren't equal as making F happen impacts E'E's chances
ANOTHER way to think about this is if E rolls a 3 then the only way to make the sum of the 2 dice equal 3 is if die 2 rolls 3 as well. Hence the pprobability Of the second outcome tht sum of 2 die=6 depends on the number the first die lands
