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2 years ago

The 6th term is 22 and the common difference is 6 what is the fiftieth term?

Mathematics

1 answer:

SOVA2 [1]2 years ago

6 0

Answer:

the fiftieth term is 76

Step-by-step explanation:

first subtract 15 by 6

15-6= 9

22+ 6 (9)

6 x 9= 54

22 + 54= 76

Answer: 76

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Kevin can travel 22 1/2miles in 1/3hour. What is his average speed in miles per hour?

Reptile [31]

Answer:

67.5 miles per hour

Explanation:

22 1/2 * 3 = 67.5

7 0

2 years ago

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A point is dilated with respect to the origin. Determine the value of K and state whether the dilation is an expansion or contra

vlabodo [156]

Scale Factor (K) = (new length/measure)/ (original length/measure)
for x-coordinate = 8/2 = 4
for y-coordinate = 16/4 = 4

K=4, expansion

K is the representation of "scale factor". Scale factor is the ratio of the lengths involved of the similar figures. It can be used to identify the kind of dilation, whether it is contraction or expansion. If the Scale Factor is greater than 1, then that means expansion and if it is less than 1, then it signifies contraction.

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3 years ago

What is the reciprocal of 2/3

galina1969 [7]

Answer:

3/2 or 1 and a half

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7 0

3 years ago

Jonas weight 63 pounds. jane weight 67 pounds. round each number to the nearest ten.

IrinaVladis [17]

Answer:

Jonas = 60 pounds

Jane = 70 pounds

Remember- 5 or more, raise the score. 4 or less, let it rest.

Jonas is 63 pounds. 3 is less than 4, so rounded to the nearest ten would be 60 pounds.

Meanwhile, Jane is 67 pounds. 7 is more than 5, so we will raise the score.

So, 67 rounded to the nearest ten would be 70.

You have your answers. 60 and 70. Hope this helps!

4 0

3 years ago

Read 2 more answers

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

3 years ago