Given
An algebraic expression is the difference between seven times a number and three times that number.
To find:
The algebraic expression.
Solution:
Let x be the unknown number.
Multiplication is used for times and subtraction is used for difference.
7 times of a number = 7x
3 times of that number = 3x
The difference between seven times a number and three times that number is
Therefore, the algebraic expression for the given statement is 7x-3x and its simplified form is 4x.
In a parallelogram consecutive angles are supplementary.
Answer:
d = 17
Step-by-step explanation:
The given arithmetic sequence is :
31, 48, 65, 82, ...
We need to find the common difference for this sequence.
First term, a₁ = 31
Second term, a₂ = 48
Common difference = a₂-a₁
= 48-31
= 17
So, the common difference for this arithmetic sequence is equal to 17.
Answer:
Ο 7 x + 4 and 3 x + 5 + 4 x - 1 When x = 2, both expressions have a value of 18.
Ο The expressions are only equivalent when evaluated with even values.
Answer:
8
Step-by-step explanation:
Key to this question is assume that each exchange preserves the total dollar amount of Nick’s money.
If He exchanges all his $5 bills for $1 bills, it means that a $5 bill will result in 5 $1 bills as such, if he had x number of $5 bill, after the exchange, he would have 5x $1 bills.
then all his $20 bills for $5 bills, it means that for each $20 bill, he gets 4 $5 bills which means that if he had y number of $5 bills, after the exchange, he would have 4y $5 bills.
and finally all his $100 bills for $20 bills, then he must have received 5 $20 bills for each $100 such that if he had z number of $100 bills before the exchange, he would have 5z number of $20 bills after the exchange. Given that originally he had 17 bills and later 77 bills then
x + y + z = 17
5x + 4y + 5z = 77
Multiplying the first equation by 5,
5x + 5y + 5z = 85
5x + 4y + 5z = 77
subtract 2 from 1
y = 8
