the answer for this question is 64-144a+108a^2-27a^3
Answer:
Step-by-step explanation:
<u>Given:</u>
- AB = 192 cm
- AC : CB = 1 : 3
- CD = BC/12
- The distance between midpoints of AD and CB = x
<u>Find the length of AC and CB:</u>
- AC + CB = AB
- AC + 3AC = 192
- 4AC = 192
- AC = 192/4
- AC = 48 cm
<u>Find CB:</u>
<u>Find the length of CD:</u>
- CD = BC/12 = 144/12 = 12 cm
<u>Find the length of AD:</u>
- AD = AC - CD = 48 - 12 = 36 cm
<u>Find the midpoint of AD:</u>
<u>Find the midpoint of CB:</u>
- m(CB) = AC + 1/2CB = 48 + 144/2 = 48 + 82 = 130 cm
<u>Find the distance between the midpoints:</u>
Answer:
rational
Step-by-step explanation:
it can be expressed as a fraction
F(x) = 3x³ - 12x² - 15x
1) Factor Outside: 3x( x² - 4x - 5)
Factor Inside: 3x(x + 1)(x - 5)
2) Set Equal To 0:
3x = 0
x + 1 = 0
x - 5 = 0
3) Solve:
x = 0, -1, 5