The answer is 6 feet 10 inches
This is the answer of this question
Answer:
See below for proof.
Step-by-step explanation:
<u>Given</u>:

<u>First derivative</u>

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<u>Second derivative</u>
<u />







<u>Proof</u>



![= \left(x+\sqrt{1+x^2}\right)^m\left[m^2-\dfrac{mx}{\sqrt{1+x^2}}+\dfrac{mx}{\sqrt{1+x^2}}-m^2\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%28x%2B%5Csqrt%7B1%2Bx%5E2%7D%5Cright%29%5Em%5Cleft%5Bm%5E2-%5Cdfrac%7Bmx%7D%7B%5Csqrt%7B1%2Bx%5E2%7D%7D%2B%5Cdfrac%7Bmx%7D%7B%5Csqrt%7B1%2Bx%5E2%7D%7D-m%5E2%5Cright%5D)
![= \left(x+\sqrt{1+x^2}\right)^m\left[0]](https://tex.z-dn.net/?f=%3D%20%5Cleft%28x%2B%5Csqrt%7B1%2Bx%5E2%7D%5Cright%29%5Em%5Cleft%5B0%5D)

Answer:
0.25
Step-by-step explanation:
Answer:
The correct option is;
10 m
Step-by-step explanation:
The parameters given are;
Height of the first pole = 20 m
Height of the second pole = 14 m
The angle the wire connected to their top makes with the horizontal = 30°
The vertical height subtended by the inclined wire, h = The difference in height between the two poles = 20 - 14 = 6 m.
Let the horizontal distance between the two poles = D
Therefore;
The horizontal length of the wire = D
From trigonometric ratios, we have;

Which gives;

The correct option is 10 m.