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sladkih [1.3K]
3 years ago
11

Melinda earns 5 minutes to play video games for every hour she spends on homework.

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

She gets 15 minutes to play video games.

Step by step:

For every 1 hour = 5 minutes, so 1x3 = 3 hours, 5x3 = 15 minutes.

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Find the equivalent fraction for 10/20
dezoksy [38]
\frac{10}{20} =  \frac{ \frac{10}{10} }{ \frac{20}{10} } =  \frac{1}{2}
6 0
3 years ago
Please help
user100 [1]

Answer:

Length of garden will be 30 metres.

Step-by-step explanation:

Let the Width of garden be x metres.

then,

Length of garden will be (x+6) metres.

Area = Length × Breadth

720 = x X (c+6)

720 = x²+6x

0 = x²+6x-720

As we can see above equation is a quadratic equation in the form of ax²+bx+C.

so,

=  \frac{ - b ±  \sqrt{{b}^{2} - 4ac}  }{2a}  \\ =   \frac{ - 6 ±   \sqrt{{6}^{2} - 4 \times 1 \times  - 720}  }{2}  \\ =    \frac{ - 6 ±  \sqrt{36 + 2880} }{2}  \\  =   \frac{ - 6 ±  \sqrt{2916} }{2}  \\  =   \frac{ - 6 ± 54}{2}\\= \frac{-6+54}{2} ... \frac{ - 6 - 54}{2}  \\  =  \frac{48}{2} ... \frac{ - 60}{2}  \\  = 24... - 30

One of the Roots of the Quadratic equation is 24 and other is -30.

And as we know width of any garden cannot be negative so the width of garden will be 24 metres.

As we got the width,

adding 6 to it will give us the Length,

So,

24 metres + 6 = 30 metres.

Length of the garden is 30 metres.

Hope It Helped You ;)

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@khuturr_

8 0
3 years ago
If a+b+c=0 then find the value of a^2+b^2+c^2/a^2-bc pls help me
VladimirAG [237]

a+b+c=0

[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]

[a^2+b^2+c^2+2ab+2ac+2bc=0]

[a^2+b^2+c^2=-(2ab+2ac+2bc)]

[a^2+b^2+c^2=-2(ab+ac+bc)] (i)

also

[a=-b-c]

[a^2=-ab-ac] (ii)

[-c=a+b]

[-bc=ab+b^2] (iii)

adding (ii) and (iii) ,we have

[a^2-bc=b^2-ac] (iv)

devide (i) by (iv)

[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
8 0
3 years ago
Circle the difference 9 - 4=5
Igoryamba
5 is the difference.

Note: Minuend - Subtrahend = Difference
3 0
3 years ago
Read 2 more answers
The following frequency table shows the number of cavities each of Dr. Freese's patients had.
Anit [1.1K]

Answer:

0

Step-by-step explanation:

13 patients had 0 cavities, according to the table! The righthand column is the frequency of people, and the left is the number of cavities they had.

6 0
3 years ago
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