Answer:
see explanation
Step-by-step explanation:
The translation represented by ![\left[\begin{array}{ccc}1\\4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
interprets as a shift of 1 unit to the right ( add 1 to x- coordinate ) and a
shift of 4 units down ( subtract 4 from the y- coordinate ), then
(1, 4 ) → (1 + 1, 4 - 4 ) → (2, 0 )
(4, 4 ) → (4 + 1, 4 - 4 ) → (5, 0 )
(6, 2 ) → (6 + 1, 2 - 4 ) → (7, - 2 )
(1, 2 ) → (1 + 1, 2 - 4 ) → (2, - 2 )
1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2
19. Perimeter of rectangle = 2(l + b)
l = 25m
b = 16m
Perimeter of rectangular park = 2 (25 + 16)
= 50 + 32
= 82m
Perimeter of square park = 82m
(given that, perimeter of rectangular and square park are equal)
Perimeter of square = 4a
4a = 82
a = 82/4
a = 20.5m
Area of square park = a²
= 20.5²
= 420.25m²
20. Perimeter of regular hexagon = 6a
a = 2.5
6a = 6 × 2.5
= 15cm
21. Perimeter of regular decagon = 10a
a = 8
10a = 10 × 8
= 80cm
It’s the light blue one!!!
